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Triss [41]
3 years ago
10

Which expression can be used to approximate the expression below,for all positive number a,b and x where a =/ 1 and b=/ 1

Mathematics
2 answers:
MAVERICK [17]3 years ago
8 0

Answer:

log_ax=\frac{log_bx}{log_ba}

Therefore, Option 1st is correct.

Step-by-step explanation:

We have given that a=1 and b=1

We need to find expression equivalent to the given expression

We have:log_ax

We have a logarithmic property:

log_my=\frac{log_ny}{log_nm}    (1)

Here, we have m=a, x=y and n=b on substituting the values in (1) we get:

log_ax=\frac{log_bx}{log_ba}

Therefore, Option 1st is correct.

And when a=1 and b=1 we get:

log_1x=\frac{log_1x}{log_11}

Vesnalui [34]3 years ago
8 0

Answer:

It's A on edge.

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How is multiplying exponents (x² ⋅ x⁴) different from raising a power to a power ((x²)⁴)?
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8 0
3 years ago
You invested a total of $15,000 at (mixed fraction) 4 1/2% and 5% simple interest. During one year, the two accounts earned $715
Sunny_sXe [5.5K]

The two investments are $7000 and $8000 during one year.

The amount $15,000 invested at 4\frac{1}{2}% and 5% simple interest.

During one year, the two accounts earned $715.

<h3>What is simple interest?</h3>

Simple interest is a method for calculating the amount of interest charged on a sum over a fixed period of time at a given rate.

Let amount x be invested at 4\frac{1}{2}%. Then, amount 15,000-x is invested at 5%.

Now, 4\frac{1}{2}×x+5×15000-x=715

⇒0.045x+0.05(15000-x)=715

⇒0.045x+750-0.05x=715

⇒750-0.005x=715

⇒0.005x=35

⇒x=$7000

Thus, x=$7000 and 15000-x=$8000

Hence, the two investments are $7000 and $8000.

To learn more about simple interest visit:

brainly.com/question/25663053

#SPJ1

8 0
2 years ago
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