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Triss [41]
3 years ago
10

Which expression can be used to approximate the expression below,for all positive number a,b and x where a =/ 1 and b=/ 1

Mathematics
2 answers:
MAVERICK [17]3 years ago
8 0

Answer:

log_ax=\frac{log_bx}{log_ba}

Therefore, Option 1st is correct.

Step-by-step explanation:

We have given that a=1 and b=1

We need to find expression equivalent to the given expression

We have:log_ax

We have a logarithmic property:

log_my=\frac{log_ny}{log_nm}    (1)

Here, we have m=a, x=y and n=b on substituting the values in (1) we get:

log_ax=\frac{log_bx}{log_ba}

Therefore, Option 1st is correct.

And when a=1 and b=1 we get:

log_1x=\frac{log_1x}{log_11}

Vesnalui [34]3 years ago
8 0

Answer:

It's A on edge.

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I’ll give 20 points for the ans and equation.
Hunter-Best [27]

Answer: I believe it would be 1.25, because 1.42 times 55000 is 78100, and 1.25 times 64000 is 80000, and 80000 is greater than 78100.

(not completely sure though, I'm not the brightest)

Step-by-step explanation:

5 0
2 years ago
Factor the expression completely. 6×3- 4×2 – 16x A. 0 B. 2x(3×2 – 2x – 8) C. 2x(3x + 4)(x – 2) D. 4x(2x + 1)(x – 4) E. 2x(2×2 +
Ghella [55]

Answer:

<h3>The answer is option C</h3>

Step-by-step explanation:

6x³ - 4x² - 16x

To factorize the expression first factor out the GCF out

The GCF in the expression is 2x

That's

2x( 3x² - 2x - 8)

Next Factorize the terms in the bracket

To factorize write - 2x as a difference

that's

2x( 3x² + 4x - 6x - 8)

<u>Factor out x from the expression</u>

2x [ x( 3x + 4) - 6x - 8 ]

<u>Next factor out - 2 from the expression</u>

2x [ x ( 3x + 4) - 2( 3x + 4) ]

<u>Factor out 3x + 4 from the expression</u>

We have the final answer as

<h3>2x( 3x + 4)( x - 2)</h3>

Hope this helps you

4 0
3 years ago
A tank contains 300 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
bonufazy [111]

Answer:

A(t) = 300 -260e^(-t/50)

Step-by-step explanation:

The rate of change of A(t) is ...

A'(t) = 6 -6/300·A(t)

Rewriting, we have ...

A'(t) +(1/50)A(t) = 6

This has solution ...

A(t) = p + qe^-(t/50)

We need to find the values of p and q. Using the differential equation, we ahve ...

A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50

0 = 6 -p/50

p = 300

From the initial condition, ...

A(0) = 300 +q = 40

q = -260

So, the complete solution is ...

A(t) = 300 -260e^(-t/50)

___

The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.

6 0
3 years ago
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I am Lyosha [343]

Amphitrite1040Answer:

Amphitrite1040

Step-by-step explanation:

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3 years ago
What is the value of 12.5 × 107?
KIM [24]
The answer is 1337.5
4 0
3 years ago
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