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melomori [17]
3 years ago
12

Im confused that's all - If 80% is 75 marks, what is full marks

Mathematics
1 answer:
never [62]3 years ago
8 0

Let the full marks be represented by = x

As given, 80% of x is 75

So,

\frac{80}{100}*x=75

x= 80x=7500

x=93.75

Hence, full marks is 93.75

We can check also- \frac{80}{100}*93.75 =75


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The mean temperature for the first 7 days in January was 6 degrees.The temperature on the 8 days was 10 degrees . What is the me
kolezko [41]

Answer: The mean temperature for the first eight days is 6.5 degrees

Step-by-step explanation: The most important piece of clue has been given which  is the mean (average) for the observed data set, which is 7 days.

Note that the formula for the mean of a data set is derived as;

Mean = ∑x / f

Where ∑x is the summation of all observed data set and f is the number of data observed, that is 7. The formula now becomes;

6 = ∑x / 7

By cross multiplication, we now have,

6 * 7 = ∑x

42 = ∑x

This means the addition of all temperature observed on the first 7 days is 42. The temperature on the eighth day is now given as 10 degrees, this means the summation of all observed data for the first eight days would become 42 + 10 which equals 52. Therefore when calculating the mean for the first eight days, ∑x is now 52. The formula for the first eight days therefore is derived as follows;

Mean = ∑x / 8

Mean = 52 / 8

Mean = 6.5

The calculations therefore show that the mean temperature for the first eight days in January is 6.5 degrees

3 0
3 years ago
Henry can write 5 1\4 pages of his novel in 3 hours.
Blababa [14]

Answer:

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Step-by-step explanation:

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3 years ago
According to a study, 50 % of adult smokers started smoking before 21 years old. 5 smokers 21 years old or older are randomly se
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Answer:

a) The probability that at least 2 of them started smoking before 21 years of age is 0.1875 = 18.75%.

b) The probability that at most 4 of them started smoking before 21 years of age is 0.96875 = 96.875%.

c) The probability that exactly 3 of them started smoking before 21 years of age is 0.3125 = 31.25%.

Step-by-step explanation:

For each smoker, there are only two possible outcomes. Either they started smoking before 21 years old, or they did not. Smokers are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

50% of adult smokers started smoking before 21 years old.

This means that p = 0.5

5 smokers 21 years old or older are randomly selected, and the number of smokers who started smoking before 21 is recorded.

This means that n = 5.

a) The probability that at least 2 of them started smoking before 21 years of age is

This is:

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.5)^{0}.(0.5)^{5} = 0.03125

P(X = 1) = C_{5,1}.(0.5)^{1}.(0.5)^{4} = 0.15625

P(X < 2) = P(X = 0) + P(X = 1) = 0.03125 + 0.15625 = 0.1875

The probability that at least 2 of them started smoking before 21 years of age is 0.1875 = 18.75%.

b) The probability that at most 4 of them started smoking before 21 years of age is

This is:

P(X \leq 4) = 1 - P(X = 5)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.5)^{5}.(0.5)^{0} = 0.03125

P(X \leq 4) = 1 - P(X = 5) = 1 - 0.03125 = 0.96875

The probability that at most 4 of them started smoking before 21 years of age is 0.96875 = 96.875%.

c) The probability that exactly 3 of them started smoking before 21 years of age is

This is P(X = 3). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{5,3}.(0.5)^{3}.(0.5)^{2} = 0.3125

The probability that exactly 3 of them started smoking before 21 years of age is 0.3125 = 31.25%.

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Step-by-step explanation:

refer the above attachment

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