Any line can be expresses as:
y=mx+b where m=slope=(y2-y1)/(x2-x1) and b=y-intercept (value of y when x=0)
First find the slope:
m=(2-0)/(8-0)=2/8=1/4 so we have thus far:
y=0.25x+b, we solve for b using any point on the line, (8,2)
2=0.25(8)+b
2=2+b
0=b
So the line is:
y=.25x which they might also express as y=x/4
The answer is E. (1/4)x
Using algebra...
n and n+2 are the integers
n*(n+2)=288
n^2+2n=288
n^2+2n-288=0
288=2*2*2*2*2*3*3=(2*2*2*2)*(2*3*3)=16*18 and 18-16=2
factor
(n+18)(n-16)=0
n+18=0
n=-18
n+2=-16
this is one solution
n-16=0
n=16
n+2=18
this is another solution
as you can see, it's just a matter of factoring
288
using arithmetic...
√288=16.97≈17
16 and 18 are the integers (as well as -16 and -18)
Answer:
AB=21 miles
Step-by-step explanation:
Since it's a right angles triangle, we'll use Pythagoras theorem
HYPOTENUSE ²= base² + perpendicular ²
Where hyp=AB, base=16 and perp=13
AB²=16²+13²
AB²=256+169
AB²=425
Taking sq root.
AB=20.6 miles
AB≈21 miles
Answer:
bread bread bread baking day
Answer:
And if we replace we got:
So we expect about 0.8 defective computes in a batch of 4 selected.
Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
Solution to the problem
For this case we have the following distribution given:
X 0 1 2 3 4
P(X) 0.4096 0.4096 0.1536 0.0256 0.0016
And we satisfy that 
and 
so we have a probability distribution. And we can find the expected value with the following formula:
And if we replace we got:
So we expect about 0.8 defective computes in a batch of 4 selected.
