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Feliz [49]
3 years ago
5

Consider a square and a regular hexagon (a 6-sided figure with sides of equal length). One side of the square is 4 feet longer t

han a side of the hexagon, and the two figures have the same perimeter. What are the lengths of the sides of each figure?

Mathematics
1 answer:
Reil [10]3 years ago
6 0
Notice the picture below

now, we know their perimeter are the same for both

thus 4(a+4) = 6a

solve for "a"

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The discounted price would be $27
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The perimeter of a square P depends on the length of its sides S this can be written in function notation as P( s) what is the b
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5 0
2 years ago
Find the second derivative of 2x^3-3y^2=8​
Umnica [9.8K]

Answer:

\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}

Step-by-step explanation:

<u>Find the first implicit derivative using implicit differentiation</u>

<u />2x^3-3y^2=8\\\\6x^2-6y\frac{dy}{dx}=0\\ \\-6y\frac{dy}{dx}=-6x^2\\ \\\frac{dy}{dx}=\frac{x^2}{y}

<u>Use the substitution of dy/dx to find the second derivative (d²y/dx²)</u>

<u />\frac{d^2y}{dx^2}=\frac{(y)(2x)-(x^2)(\frac{dy}{dx})}{y^2}\\ \\\frac{d^2y}{dx^2}=\frac{2xy-(x^2)(\frac{x^2}{y})}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{2xy-\frac{x^4}{y}}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}

5 0
3 years ago
SOLVE FAST BRAINLIEST ASAP <br><br> Y-9=41
Fudgin [204]

Answer:

Y = 50

Step-by-step explanation:

Solve for Y:

Y - 9 = 41

Add 9 to both sides:

Y + (9 - 9) = 9 + 41

9 - 9 = 0:

Y = 41 + 9

41 + 9 = 50:

Answer:  Y = 50

8 0
4 years ago
Read 2 more answers
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Pavlova-9 [17]

For this case we must express the following expression algebraically:

<em>"The quotient of b and 2 minus 4 is at least 26"</em>

So we have to:

The quotient of b and 2 minus 4, is represented as:\frac {b} {2-4}

We have different signs subtracted and the sign of the major is placed:

\frac {b} {- 2}

Thus, the expression is written as:

\frac {b} {2-4} \geq26\\\frac {b} {- 2} \geq26\\- \frac {b} {2} \geq26

ANswer:

\frac {b} {2-4} \geq26

3 0
3 years ago
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