KHP molarity = (3.5/204.22) x (1000/50) = 0.343 M
NaOH volume = 24.65 - 1.85 = 22.8 ml
Molarity of NaOH = (weight/40) x (1000/22.8) = 1.096W
KH₂PO₄ + NaOH → NaKHPO₄ + H₂O
initial 0.343 1.096W 0 0
after reaction (0.343 - 1.096W) 0 1.096W 1.096W
KH₂PO₄ and NaKHPO₄ is considered as buffer and its (H₂PO₄⁻) pKa value is 7.21
phenolphthalein indicator turns pink means it is at the equivalence point
so pH = pKa
by using buffer equation
pH = pKa + log [salt] / [acid]
when pH = pKa so [salt] = [acid]
1.096 W = 0.343 - 1.096W
2.192 W = 0.343
W = 0.156 g
NaOH molarity = 1.096 W = 1.096 x 0.156 = 0.17 M
Molarity of NaOH = 0.17 M
Answer:
man ion even know but u fr struggling today huh?
Explanation:
Parasitism relationship, where one takes something (leeches off) the other
Answer: seen below.
Explanation: since the different means use in treating rabbit muscle mitochondria containing PDH complex. I will give different reactions that occurs.
The mitochondria preparation responds as follow;
Active pyruvate dehydrogenase (dephosphorylated) is converted to inactive pyruvate dehydrogenase (phosphorylated) and the rate of conversion of pyruvate to acetyl-CoA decreases.
The phosphoryl group on pyruvate dehydrogenase (dephosphorylated) phosphate is removed enzymatically to give active pyruvate dephosphorylated which increases the rate of conversion of pyruvate to acetyl-CoA.
Malonate inhibit succinate dehydrogenase, and citrate accumulates. Accumulation of this citrate inhibits citrate synthase, and acetyl-CoA accumulates. Increased level of this acetyl-CoA inhibits pyruvate dephosphorylated and the rate of conversion of pyruvate to acetyl-CoA decreases.
Answer : The molarity of solution is, 1.73 mole/L
Explanation :
The relation between the molarity, molality and the density of the solution is,
where,
![d=M[\frac{1}{m}+\frac{M_b}{1000}]](https://tex.z-dn.net/?f=d%3DM%5B%5Cfrac%7B1%7D%7Bm%7D%2B%5Cfrac%7BM_b%7D%7B1000%7D%5D)
d = density of solution = 
m = molality of solution = 2.41 mol/kg
M = molarity of solution = ?
= molar mass of solute (toluene) = 92 g/mole
Now put all the given values in the above formula, we get the molality of the solution.
![0.876g/ml=M\times [\frac{1}{2.41mol/kg}+\frac{92g/mole}{1000}]](https://tex.z-dn.net/?f=0.876g%2Fml%3DM%5Ctimes%20%5B%5Cfrac%7B1%7D%7B2.41mol%2Fkg%7D%2B%5Cfrac%7B92g%2Fmole%7D%7B1000%7D%5D)
Therefore, the molarity of solution is, 1.73 mole/L
