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Oksi-84 [34.3K]
4 years ago
11

When working problems on the calculator for trig functions, what are you supposed to have your calculator set to?

Mathematics
1 answer:
9966 [12]4 years ago
4 0

Answer:

Degrees

Step-by-step explanation:

dont need one

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Find all solutions to the equation in the interval [0, 2π). cos 2x - cos x = 0
Jlenok [28]
This is the concept of algebra, to solve the expression we proceed as follows;
cos 2x-cosx=0
cos 2x=cosx
but:
cos 2x+1=2(cos^2x)
thereore;
from:
cos 2x=cos x
adding 1 on both sides we get:
cos 2x+1=cos x+1
2(cos^2x)=cosx+1
suppose;
cos x=a
thus;
2a^2=a+1
a^2-1/2a-1/2=0
solving the above quadratic we get:
a=-0.5 and a=1
when a=-0.5
cosx=-0.5
x=120=2/3π
when x=1
cos x=1
x=0
the answer is:
x=0 or x=2/3π

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3 years ago
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Which of the following are solutions to 2x^2-8x-90
Lorico [155]

Answer:

2(x-9)(x+5)

Step-by-step explanation:

6 0
3 years ago
you saved $10,943.89 in an emergency fund. One fourth is in a regular savings account at a 3.5% APR and the remainder is in a 30
Naddika [18.5K]
4.57%−3.5%
=1.07%

(0.0107×10,943.89)÷12
=9.76
8 0
3 years ago
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Find the projection of u = <–6, –7> onto v = <1, 1> a. <-13/2,-13/2> b. <39,91/2> c. <-13/1764,-13/17
Alexandra [31]
<h2>Answer:</h2>

a. <-13/2,-13/2>

<h2>Step-by-step explanation:</h2>

The projection of a vector u onto another vector v is given by;

proj_vu = (\frac{u.v}{|v|^2})v               ----------------(i)

Where;

u.v is the dot product of vectors u and v

|v| is the magnitude of vector v

Given:

u = <-6, -7>

v = <1, 1>

These can be re-written in unit vector notation as;

u = -6i -7j

v = i + j

<em>Now;</em>

<em>Let's find the following</em>

(i) u . v

u . v = (-6i - 7j) . (i + j)

u . v = (-6i) (1i) + (-7j)(1j)          [Remember that, i.i = j.j = 1]

u . v = -6 -7 = -13

(ii) |v|

|v| = \sqrt{(1)^2 + (1)^2}

|v| = \sqrt{2}

<em>Substitute these values into equation (i) as follows;</em>

proj_vu = [\frac{-13}{(\sqrt{2}) ^2}][i + j]

proj_vu = \frac{-13}{2} [i + j]

This can be re-written as;

proj_vu = \frac{-13}{2}i + \frac{-13}{2}j

proj_vu =

5 0
3 years ago
In which of the tables below x and y are inversely proportional? Find the constant of variation. PLZ PLZ PLZ PLZ PLZ PLZ HELP WI
nikitadnepr [17]

The answer is B

Step-by-step explanation:

the table B represent an inverse variation, the constant of variation k is 30

6 0
3 years ago
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