Answer:
Present Value = ![X [\frac{1}{(1 + 0.12)^{1} } + \frac{1}{(1 + 0.12)^{2} } + \frac{1}{(1 + 0.12)^{3} } + \frac{1}{(1 + 0.12)^{4} } + \frac{1}{(1 + 0.12)^{5} } ]](https://tex.z-dn.net/?f=X%20%5B%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B1%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B2%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B3%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B4%7D%20%7D%20%20%2B%20%5Cfrac%7B1%7D%7B%281%20%2B%200.12%29%5E%7B5%7D%20%7D%20%5D)
Step-by-step explanation:
To find - If discount rate is 12%, the present value of Rs X received at the end of each year for the next five years is equal to .... ?
Solution -
We know that, formula for finding the Present vale is given by
Present value = Future value / (1 + r)ⁿ
where r is the rate of interest
and n is Number of periods
Now,
Here in the question, we have
r = 12% = 12/100 = 0.12
n = 5
Also, Given that, we have received Rs X at the end of each year
So,
Present Value = 
=
⇒Present Value =
Answer:
15 seconds
Step-by-step explanation:
How did i get this answer? It is apparent that the girl is capable of running 6 2/3 metres per one second and she must run 100 metres.
First, let's convert 2/3 into a decimal so that it is easier to calculate later. 2/3=0.667 (you can also just do 2 divide by 3 and will end up with the same number)
Now our numbers are 6.667 and 100. Let's divide 100 by 6.667 which estimates to 15
If x is the game number, and y is the amount of touchdown passes for that specific game number, then (5,3) represents the idea that the quarter back threw y = 3 touchdown passes for game number x = 5
So the answer is choice D. This is the only ordered pair that comes from the given table. Something like (2,4) isn't true because the quarterback threw 1 touchdown pass (not 4) in game two.
Exact form: 7/12
decimal form: 0.583 (repeating sign over 3)
An arithmetic sequence is a sequence with the difference between two consecutive terms constant. The difference is called the common difference. A geometric sequence is a sequence with the ratio between two consecutive terms constant. This ratio is called the common ratio.
