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GenaCL600 [577]
2 years ago
12

How many odd numbers are greater than 30 and less than 40?

Mathematics
1 answer:
Lana71 [14]2 years ago
3 0

Answer:

5 odd numberis there 31,33,35,37,39

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The first element in an arithmetic sequence is 2. Its twenty second is 14. Find the value of n so that a(n)=6
Aleks04 [339]

Answer:

<h2>n = 8</h2>

Step-by-step explanation:

Given the nth term of an arithmetic sequence to be Tn = a+(n-1)d

a = first term of the sequence

n = number of terms

d = common difference.

Given the first element a = 2 and 22nd to be 14

T22 = a+(22-1)d = 14

a+21d = 14

Substtuting a = 2 into the equation to get d

2+21d = 14

21d = 12

d = 12/21

d = 4/7

The nth term of the sequence given a = 2 and d = 4/7 will be expressed as;

Tn = 2+(n-1)4/7

Given Tn = 6

6 = 2+(n-1)4/7

6 = 2+4/7 n - 4/7

6-2+4/7 = 4/7 n

32/7=4/7 n

32 = 4n

n = 32/4

n = 8

8 0
3 years ago
It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

4 0
3 years ago
−3x+5y=2x+3y ordered pairs
NeTakaya

Answer:

y=5/2x

Step-by-step explanation:

5x=2y

y=5/2x

you cant get ordered pairs from this directly you will only get an equation

6 0
2 years ago
F(x)=2x and g(x)=square root of x what is the domain of f(g(x))?
Dmitriy789 [7]

Answer:

x\ge 0

Step-by-step explanation:

The given functions are:

f(x)=2x


and


g(x)=\sqrt{x}


Now,

f(g(x))=f(\sqrt{x} )


f(g(x))=2\sqrt{x}

The domain refers to values of x for which f(g(x))=2\sqrt{x} is defined.


The  expression under the radical sign must not be negative.

The domain is

x\ge 0

5 0
2 years ago
Find the values of x and z
Ad libitum [116K]
Hope this helps you, and good luck in the future :)

4 0
3 years ago
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