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Zina [86]
3 years ago
7

Use the image above to identify and explain the relationship between the segments and circles A and B. In your explanation, be s

ure to include specific vocabulary and definitions for the relationships.
ER

Mathematics
1 answer:
Sergio [31]3 years ago
3 0

Answer:

Step-by-step explanation:

From the given figure, it can be seen that there are two circles with centers A and B respectively. The circle with the center A is larger in size than the circle with center B. Points P, Q and E lie on the surface of the circle having center A and R, S, C and T points lie on the circle having center B.

One tangent passes from the point  Q of the one circle to the point T of the another circle and the other tangent passes from point R of the smaller circle to the point E of the larger circle. These two tangents intersects each other outside both the circle. There is another tangent which passes from the point C of the smaller circle to a point D lying outside the circle.

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Solve 6 1/2 + 7 3/8 - 6 1/2
Amiraneli [1.4K]

Answer:

Step-by-step explanation:

6 1/2 - 6 1/2 + 7 3/8 =

0 + 7 3/8 = 7 3/8

3 0
3 years ago
This makes no sense to me, help please
kondaur [170]

Step-by-step explanation:

The expression is: 7 × -5 - 7

The value of the expression is: -42

-35 - 7 = -42

6 0
3 years ago
Read 2 more answers
Diagram below shows the curve of a quadratic function
uranmaximum [27]

Answer:

q = -8, k = 2.

r = -6.

Step-by-step explanation:

f(x) = (x - p)^2 + q

This is the vertex form of a quadratic where the vertex is at the point (p, q).

Now the x intercepts are at -6 and 2 and the curve is symmetrical about the line x = p.

The value of p is the midpoint of  -6 and 2 which is (-6+2) / 2 = -2.

So we have:

f(x) = 1/2(x - -2)^2 + q

f(x) = 1/2(x + 2)^2 + q

Now the graph passes through the point (2, 0) , where it intersects the x axis, therefore, substituting x = 2 and f(x) = 0:

0 = 1/2(2 + 2)^2 + q

0 = 1/2*16 + q

0 = 8 + q

q = -8.

Now convert this to standard form to find k:

f(x) = 1/2(x + 2)^2 - 8

f(x) = 1/2(x^2 + 4x + 4) - 8

f(x) = 1/2x^2 + 2x + 2 - 8

f(x) = 1/2x^2 + 2x - 6

So k = 2.

The  r  is the y coordinate when x = 0.

so r = 1/2(0+2)^2 - 8

=  -6.

3 0
4 years ago
PLEASE ANSWER QUICKLY WITH DESCRIPTION ON HOW TO DO IT!!! If (-a^2b3)(2ab^2)(-3b)=ka^mb^n what is the value of m+n????
iragen [17]

Answer:

m+n=9

Step-by-step explanation:

Put the equation into the form ka^mb^n by multiplying the coefficients (-1*2*-3), so k= 6, then add the exponents of a together, a^2+a^1= a^3, m=3.

Now you have 6a^3, next we do the exponents of b together, b^3, b^2, b^1= b^6, n=6.

This is 6a^3b^6. m=3 and b=6, so add m+n=9.

6 0
3 years ago
HELPP<br> Simplify the expression 6^3+ 5(4 − 2).<br><br> 28<br> 36<br> 226<br> 234
mamaluj [8]

Answer:

BODMAS

{6}^{3 }  + 5(4 - 2) = 216 + 5(2)   \\  = 216 + 10 \\  = 226

5 0
2 years ago
Read 2 more answers
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