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2 years ago

Which system of equations does the graph represent?

Mathematics

1 answer:

zubka84 [21]2 years ago

8 0

Your answer should be the last one. All you do is put your x&y intercept into the equation. It’s pretty simple and easy

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What is the remainder for the synthetic division problem below?

Tcecarenko [31]

The full answer would be x^2 + 8x + 16 + (54/(x-3)). Therefore, the remainder would be A. 54.

Hope this helps!

6 0

2 years ago

Read 2 more answers

It takes Ty 4 hours 30 minutes to read his favorite book, reading at a constant rate of 100 pages

AysviL [449]

Answer:

540 pages

Step-by-step explanation:

100 pages = 50 mins

??? pages = 270 mins (converted 4hrs 30 mins to minutes)

Now you could cross multiply to find what the number of pages are:

100 pages x 270 mins = 50 mins x ??? pages

27000 = 50 mins x ??? pages

27000/50 = ??? pages

540 = ??? pages

So there are 540 pages in his favourite book.

8 0

2 years ago

What is the area of triangle FGH? Round your answer to the nearest tenth of a square centimeter.

Misha Larkins [42]

Answer:

Step-by-step explanation:

8 0

2 years ago

In triangle ABC, D is the midpoint of side AB and E is the midpoint of side BC. The area of triangle ABC is 56 square units. Fin

Tju [1.3M]

Answer:

YourMom Not Cool

Step-by-step explanation:

yourMom is not cool

STOP CHEATING AND TRYING TO SEE ANSWER

8 0

1 year ago

You decide to put $5000 in a savings account to save $6000 down payment on a new car. If the account has an interest rate of 7%

bezimeni [28]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill&\$6000\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years \end{cases}$

$\bf 6000=5000\left(1+\frac{0.07}{12}\right)^{12\cdot t}\implies \cfrac{6000}{5000}\approx (1.0058)^{12t}\implies \cfrac{6}{5}\approx(1.0058)^{12t} \\\\\\ \log\left( \cfrac{6}{5} \right)\approx \log[(1.0058)^{12t}]\implies \log\left( \cfrac{6}{5} \right)\approx 12t\log(1.0058) \\\\\\ \cfrac{\log\left( \frac{6}{5} \right)}{12\log(1.0058)}\approx t\implies 2.63\approx t\impliedby \textit{about 2 years, 7 months and 16 days}$

6 0

2 years ago