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3 years ago

INTELLIGENT STUDENT IN TRIG?.Ill give brainlest

Mathematics

1 answer:

faltersainse [42]3 years ago

8 0

Answers:

x = 6

y = 6*sqrt(2)

=======================

Explanation:

To find these values, you can use the general template of a 45-45-90 triangle or you can use trig ratios

tan(45) = 1

tan(angle) = opposite/adjacent

tan(45) = x/6

1 = x/6

6*1 = x

x = 6

-------

sin(45) = 1/sqrt(2)

sin(angle) = opposite/hypotenuse

sin(45) = 6/y

1/sqrt(2) = 6/y

1*y = sqrt(2)*6

y = 6*sqrt(2)

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3 years ago

Plz help me out with this

nadya68 [22]

Given,

HK is the perpendicular bisector of GJ. So, GK = KJ.
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Find KJ .

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First find the value of x

$\sf \: GK \: = KJ \\\sf 2x + 10 = 3x - 15 \\\sf 2x - 3x = - 15 - 10 \\ \sf - x = - 25 \\ \sf \: - > \boxed{\bf \: x = 25}$

Now, find the value of KJ.

$\sf3x - 15 \\ \sf= 3(25) - 15 \\ \sf=7 5 - 15 \\ = \boxed{\bf \: 60}$

-> The value of KJ is 60.

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2 years ago

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2 years ago

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Verbal expression x to the third power times y to the 4th power???

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2 years ago

On a True/False test, Amy answered the first three questions wrong but answered the rest of the questions correctly. On the same

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3 years ago

INTELLIGENT STUDENT IN TRIG?.Ill give brainlest​

INTELLIGENT STUDENT IN TRIG?.Ill give brainlest