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Natali5045456 [20]
3 years ago
9

What is an equation of the line through (-1,-4) and parallel to the line 3x+y=s

Mathematics
1 answer:
timofeeve [1]3 years ago
4 0

line: 3x + y = s

y = s - 3x

To two lines be parallel both angular coeficients need to be equal

In y = s - 3x our angular coeficient is -3

y = ax + b where a is angular and b is linear

Now we have the equation

(y - yo) = m.(x - xo)

(y - (-4)) = -3.(x - (-1))

y + 4 = -3.(x + 1)

y + 4 = -3x - 3

y = -3x - 3 - 4

y = -3x - 7 is parallel to y = -3x + s

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(N^3 - N^4) - (3n^3- 7n^4)
Free_Kalibri [48]
If you would like to solve (n^3 - n^4) - (3n^3 - 7n^4), you can do this using the following steps:

(n^3 - n^4) - (3n^3 - 7n^4) = <span>n^3 - n^4 - 3n^3 + 7n^4 = n^3 - 3n^3 - n^4 + 7n^4 = -2n^3 + 6n^4
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Question Help James and Bethany Morrison are celebrating their 10th anniversary by having a reception at a local reception hall.
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Read 2 more answers
What is b?<br> − ( 3 − 6b ) = 6b + 5
zubka84 [21]

Answer:

-1 1/2

Step-by-step explanation:

-(3-6b)=6b + 5 .remember to balance!!!!

-6b + 6b= 6b + 6b

-3=12b+5

-3+5=5-5

-8=12b   now divide since its the inverse operation

think 12/-8= -1 1/2

so B equals - 1 1/2

3 0
3 years ago
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