I’m pretty sure it would be 1/5, because scaling is changing the y values of the function. If the y value of the original is 10, you need to multiply/scale the new one by 1/5 to get the y value of 2
One can know if an equation is extraneous if after plugging it in the original equation, it shows a false meaning or the value is undefined.
<h3>What is an extraneous equation?</h3>
It should be noted that an extraneous equation means a root of a transformed equation that isn't the root of the original equation due to the fact that it's excluded from the domain of the original equation.
In this case, one can know if an equation is extraneous if after plugging it in the original equation, it shows a false meaning or the value is undefined.
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With what? I would love to help you
Answer:
1/337500
(Decimal: 0.000003)
Step-by-step explanation:
