Question

Nathaniel bought 3 hamburgers and 2 orders of fries for $12.50. Liam bought 2 hamburgers and 4 orders of fries for $13. How much would an order of 1 hamburger and 2 orders of fries cost?

Answer 1

The cost of an order of 1 hamburger and 2 orders of fries cost which Nathaniel and Liam bought is $6.5.

What is system of equation?

A system of equation is the set of equation in which the finite set of equation is present for which the common solution is sought.

Let the cost of 1 hamburger is x dollar and 2 orders of fries is y dollars. Nathaniel bought 3 hamburgers and 2 orders of fries for $12.50. Thus,

$3x+2y=12.5$

Solve this equation as,

$2y=12.5-3x\\y=\dfrac{12.5-3x}{2}$                        .....1

Liam bought 2 hamburgers and 4 orders of fries for $13. Thus,

$2x+4y=13$

Put the value of y in this equation and solve it further,

$2x+4(\dfrac{12.5-3x}{2})=13\\2x+25-6x=13\\-4x=13-25\\-4x=12\\x=\dfrac{12}{4}\\x=3$

Put this value of x in equation 1,

$y=\dfrac{12.5-3\times3}{2}\\y=\dfrac{3.5}{2}\\y=1.75$

The cost of an order of 1 hamburger and 2 orders of fries is,

$C=3\times 1+2\times1.75\\C=3+3.5\\C=6.5$

Thus, the cost of an order of 1 hamburger and 2 orders of fries cost which Nathaniel and Liam bought is $6.5.

Learn more about the system of equations here;

brainly.com/question/13729904

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