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Murljashka [212]

2 years ago

8

Nathaniel bought 3 hamburgers and 2 orders of fries for $12.50. Liam bought 2 hamburgers and 4 orders of fries for $13. How much

would an order of 1 hamburger and 2 orders of fries cost?

1 answer:

Nina [5.8K]2 years ago

3 0

The cost of an order of 1 hamburger and 2 orders of fries cost which Nathaniel and Liam bought is $6.5.

<h3>What is system of equation?</h3>

A system of equation is the set of equation in which the finite set of equation is present for which the common solution is sought.

Let the cost of 1 hamburger is x dollar and 2 orders of fries is y dollars. Nathaniel bought 3 hamburgers and 2 orders of fries for $12.50. Thus,

$3x+2y=12.5$

Solve this equation as,

$2y=12.5-3x\\y=\dfrac{12.5-3x}{2}$ .....1

Liam bought 2 hamburgers and 4 orders of fries for $13. Thus,

$2x+4y=13$

Put the value of y in this equation and solve it further,

$2x+4(\dfrac{12.5-3x}{2})=13\\2x+25-6x=13\\-4x=13-25\\-4x=12\\x=\dfrac{12}{4}\\x=3$

Put this value of x in equation 1,

$y=\dfrac{12.5-3\times3}{2}\\y=\dfrac{3.5}{2}\\y=1.75$

The cost of an order of 1 hamburger and 2 orders of fries is,

$C=3\times 1+2\times1.75\\C=3+3.5\\C=6.5$

Thus, the cost of an order of 1 hamburger and 2 orders of fries cost which Nathaniel and Liam bought is $6.5.

Learn more about the system of equations here;

brainly.com/question/13729904

#SPJ1

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When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.

Substitute these into the given differential equation:

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Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.

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It should be easy enough to see that

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