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IgorC [24]
3 years ago
11

Judy Clark went to Reel Bank. She borrowed $7,800 at a rate of 6 1/2%. The date of the loan was September 2. Judy hoped to repay

the loan on January 20. Assuming the loan is based on ordinary interest, Judy will pay back on January 20: ____________
Mathematics
1 answer:
abruzzese [7]3 years ago
8 0

Answer:

$7995.85

Step-by-step explanation:

We will use simple interest formula to solve our given problem.

A=P(1+rt), where,

A = Amount after t years,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

r=6.5\%=\frac{6.5}{100}=0.065

t=\text{141 days}=\frac{141}{365}\text{ year}

A=\$78001+0.065\times \frac{141}{365})

A=\$7800(1+0.065\times 0.38630136986)

A=\$7800(1+0.025109589041)

A=\$7800(1.025109589041)

A=\$7995.85479

A\approx \$7995.85

Therefore, Judy will will pay back on January 20: <u>$7995.85</u>.

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Marianna [84]

Answer:

The probability that the average age of a randomly selected sample of 100 students will be less than 21.8 years is 0.159

Step-by-step explanation:

According to the given data we have the following:

mean = μ= 22

standard deviation = σ = 2

n = 100

μx = 22

σx=σ/√n=2/√100=0.2

Therefore, P( x < 21.8)=P(x-μx)/σx<(21.8-22)/0.2

=P(z<-1)

= 0.159

The probability that the average age of a randomly selected sample of 100 students will be less than 21.8 years is 0.159

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The probability that an event will occur is fraction 2 over 3 . Which of these best describes the likehood of the event occurrin
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4 0
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Dennis_Churaev [7]
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Therefore, a = 4 and b = 3.

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