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Nikitich [7]
2 years ago
7

A number is divided into two parts, such that one part is 10 more than the other. If the two parts are in the ratio 5:3, find th

e number and the two parts.
Mathematics
1 answer:
Triss [41]2 years ago
4 0

Answer:

25 and 15  

Step-by-step explanation:

Since we were given two parts to be in ratio 5:3

the first number is then 5x , and second number 3x

Note that the second number is more than the first so it becomes

3x + 10

5x = 3x +10,     5x - 3x = 10

2x = 10,     x = 5

from the question,  we find the two parts ;

the first number would be 5x

5 x 5 = 25

and second number, 3x = 3x 5 = 15

so the two numbers are  25 and 15..    25 + 15 = 40

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Answer:

1) 32m^{6}n^{14}

2) 3j^{4}k^{8}

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Step-by-step explanation:

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to know: when dividing terms with same base and exponents, divide the bases and subtract the exponents

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2) (15j^{5}k^{2}· 25j²k^{9}) ÷ 5³j³k³ = (375j^{7}k^{11}) ÷ 125j³k³ = 3j^{4}k^{8}

3) (5 · 3³) a^{11}b^{16} = 135a^{11}b^{16}

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