<span>C. 7x/9y is the correct answer.
</span>
The question is incomplete. Here is the complete question.
m∠J and m∠Kare base angles of an isosceles trapezoid JKLM.
If m∠J = 18x + 8, and m∠M = 11x + 15 , find m∠K.
A. 1
B. 154
C. 77
D. 26
Answer: B. m∠K = 154
Step-by-step explanation: <u>Isosceles</u> <u>trapezoid</u> is a parallelogram with two parallel sides, called Base, and two non-parallel sides that have the same measure.
Related to internal angles, angles of the base are equal and opposite angles are supplementary.
In trapezoid JKLM, m∠J and m∠M are base angles, so they are equal:
18x + 8 = 11x + 15
7x = 7
x = 1
Now, m∠K is opposite so, they are supplementary, which means their sum results in 180°:
m∠J = 18(1) + 8
m∠J = 26
m∠K + m∠J = 180
m∠K + 26 = 180
m∠K = 154
The angle m∠K is 154°
Answer:
900.
Step-by-step explanation:
The first 6 square numbers are 1, 4, 9, 16, 25, 36,
The required product is 25 * 36
= 900.
Answer:
I: 82.1
Step-by-step explanation:
Mass of freight train: 9.98 • 106
= 1057.88 kg
mass of aircraft carrier: 7.3 • 107
= 781.1 kg
difference: 1057.88 - 781.1
= 276.78 kg
= 2.7678 x 10^2
