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3 years ago

If K is the midpoint of JL, JK = 8x+11 and KL = 14x-1, find JL.

Mathematics

2 answers:

gladu [14]3 years ago

7 0

Step-by-step explanation:

Since, K is the midpoint of JL.

$\therefore \: JK = KL \\ 8x + 11 = 14x - 1 \\ 11 + 1 = 14x - 8x \\ 12 = 6x \\ \frac{12}{6} = x \\ 2 = x \\ \\ \because \: JL = JK + KL \\ \therefore \: JL = 8x + 11 + 14x - 1 \\ \therefore \: JL = 8x + 14x + 11 - 1 \\ \therefore \: JL = 22x + 10\\ \therefore \: JL = 22 \times 2 + 10..(plug \: x = 2) \\ \therefore \:JL = 44 + 10 \\ \huge \red{ \boxed{\therefore \:JL = 54}}$

harkovskaia [24]3 years ago

6 0

Answer:

JL=54

Step-by-step explanation:

done the topic

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At time t=0 water begins to drip out of a pipe into an empty bucket. After 56 minutes 8 inches of water are in the bucket. What

oksano4ka [1.4K]

Answer:

The linear function of the bucket is $y = \frac{1}{7}\cdot x$ , where $y$ represents the amount of water, measured in inches, and $x$ is the time, measured in minutes.

Step-by-step explanation:

According to the Euclidean and Analytical Geometries, we can construct a line by knowing two distinct points on a plane. Besides, we know two different conditions for the bucket:

Initial condition of the bucket

$A(x,y) = (0\,min, 0\,in)$

Final condition of the bucket

$B(x,y) = (56\,min, 8 in)$

The equation of the line is defined by the following model:

$y = m\cdot x + b$ (1)

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$b$ - y-Intercept, dimensionless.

$m$ - Slope, dimensionless.

Based on the known conditions of the bucket, we obtain the following system of linear equations:

$b = 0$ (2)

$56\cdot m +b = 8$ (3)

The solution of the system of equations is:

$m = \frac{1}{7}$ and $b = 0$

Then, the linear function of the bucket is $y = \frac{1}{7}\cdot x$ , where $y$ represents the amount of water, measured in inches, and $x$ is the time, measured in minutes.

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3 years ago

How do you write x^3/11 in radical form

valentinak56 [21]

Answer:

$\sqrt[11]{x^3}$