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UkoKoshka [18]
3 years ago
13

What it 55/100 in simplest form

Mathematics
2 answers:
fredd [130]3 years ago
8 0
55 / 5 = 11
100 / 5 = 20
So your answer would be 11/20
den301095 [7]3 years ago
6 0
55/100 = (55:5)/(100:5) = 11/20

55/100 = 0.55
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80% of x is equal to 100.<br><br> Find x.
xeze [42]

The number is 125 and the equation is 0.8x = 100

Step-by-step explanation:

80% of x is equal to 100.

Write an equation that shows the relationship of 80%, x, and 100

80% = 0.8

0.8x = 100

x = 100/0.8

x = 125

The number is 125 and the equation is 0.8x = 100

5 0
3 years ago
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A safety regulation states that the height hh of a guardrail should be 106 centimeters with an absolute deviation of no more tha
AlexFokin [52]
Well 106 divided by 7 is 15 so 15 times 7 is 106
6 0
3 years ago
The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s
stepladder [879]
When the direction is reversed  velocity = 0 

v = ds/dt =  6t^2 - 42t + 60 = 0

t^2 - 7t + 10 = 0

(t - 5)(t - 2) = 0

t = 2 s  and 5 s   which are the times when the direction is reversed
Position at t = 2 =  2(2)^3 - 21(2)^2 +60(2) + 3 =  55 feet
  at t = 5  position =  28 feet

Acceleration  = dv/dt = 12t - 42

At t = 2  acceleration =  -18 ft s-2
At  t = 5   ...............    = 18 ft s-2


6 0
4 years ago
Find the missing value so that the two points have a constant of proportionality of ½. (14,7) and (6,y) *
melomori [17]

Answer:

y=3

Step-by-step explanation:

\frac{7-y}{14-6} = \frac{1}{2}

\frac{7-y}{8} = \frac{1}{2}

7-y = 4

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6 0
3 years ago
A data set lists earthquake depths. The summary statistics are nequals300​, x overbarequals5.89 ​km, sequals4.44 km. Use a 0.01
kirza4 [7]

Answer:

Null hypothesis H_0:\mu=5.00km

Alternative hypothesis H_1:\mu\neq 5.00km

The p value is 0.000517, which is less than the significance level 0.01, therefore we reject the null hypothesis and conclude that population mean is not equal to 5.00.

Step-by-step explanation:

It is given that a data set lists earthquake depths. The summary statistics are

n=300

\overline{x}=5.89km

s=4.44km

Level of significance = 0.01

We need to test the claim of a seismologist that these earthquakes are from a population with a mean equal to 5.00.

Null hypothesis H_0:\mu=5.00km

Alternative hypothesis H_1:\mu\neq 5.00km

The formula for z-value is

z=\frac{\overline{x}-\mu}{\frac{s}{\sqrt{n}}}

z=\frac{5.89-5.00}{\frac{4.44}{\sqrt{300}}}

z=\frac{0.89}{0.25634351952}

z=3.4719

The p-value for z=3.4719 is 0.000517.

Since the p value is 0.000517, which is less than the significance level 0.01, therefore we reject the null hypothesis and conclude that population mean is not equal to 5.00.

6 0
3 years ago
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