Answer:
0
Step-by-step explanation:
R
Answer:
first one is 90
second one is 108
Step-by-step explanation:
Given data:
The first set of equations are x+y=4, and x=6.
The second set of equations are 3x-y=12 and y=-6.
The point of intersection of first set of te equations is,
6+y=4
y=-2
The first point is (6, -2).
The point of intersection of second set of te equations is,
3x-(-6)=12
3x+6=12
3x=6
x=2
The second point is (2, -6).
The equation of the line passing through (6, -2) and (2, -6) is,

Thus, the required equation of the line is y=x-8.
As given by the question
There are given that the point of two-line

Now,
From the condition of a parallel and perpendicular line
If the slopes are equal then the lines are parallel
If the slopes are negative reciprocal then the lines are perpendicular
If the slopes are neither of the above are true then lines are neither
Then,
First, find the slope of both of line
So,
For first-line, from the formula of slope

Now,
For second-line,

The given result of the slope is negative reciprocal because

Hence, the slope of line1 is -1/2, and slope of line2 is 2 and the lines are perpendicular.