Answer:
There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:
24x2+25x−47=(−8x−3)(ax−2)−53
You should then multiply (−8x−3) and (ax−2) using FOIL
("First, Outer, Inner, Last")
24x2+25x−47=−8ax2−3ax+16x+6−53
Then, reduce on the right side of the equation
24x2+25x−47=−8ax2−3ax+16x−47
Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.
The other option which is longer and more tedious is to attempt to plug in all of the answer choices for a and see which answer choice makes both sides of the equation equal. Again, this is the longer option, and I do not recommend it for the actual SAT as it will waste too much time.
soo the final answer is B -3
Answer: The answer Is A!
Explanation: Got it right on Edge! :))
Complex conjugates are two complex numbers and so must occur in pairs
- That is if there is 3 + i
- There must also be 3 - i
- X=(3+i) X=(3-i)
The conjugate root theorem tell us t that when the complex number a + bi is a root of a polynomial P(x) in one variable with real coefficients, then the complex conjugate a - bi is also a root of that polynomial.
Complex conjugates are often referred to as two complex numbers, that is they have 2 forms a + bi,
- a = real part of a complex numbers
- i = √ -1.
- bi = imaginary part of complex number
The two complex numbers are often referred to as conjugates of each other. That is they will have the same real part and their imaginary parts are negatives of each other.
Example are:
- a+ bi is a - bi.
- 5 + 3i is 5 - 3i
Conclusively we can therefore say that getting the complex conjugate of a complex number entails changing the sign of the imaginary part of the number.
- That is if there is 3 + i
- There must also be 3 - i
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