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alina1380 [7]
3 years ago
8

Please help me by 5 minutes

Mathematics
2 answers:
vodomira [7]3 years ago
5 0
It's an acute triangle
vampirchik [111]3 years ago
3 0
It is an acute triangle.
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Ksenya-84 [330]

Mean: 11.4

Median: 7

Mode: there isn't one


Mean: 1+5+7+12+32=57 57÷5=11.4

Median: 1, 5, 7, 12, 32. 7 is the middle number.

Mode: there isnt a number that repeats itself.

6 0
4 years ago
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Which of the following best describes the solution to the equation below?
kozerog [31]
D)One solution. b=5
Distribute 2 times b plus 2 times 3
2b+6
2b+6+2b=26
Combine like terms 4b+6=26
Subtract 6 from both sides
4b=20
Divide both sides by 4
b=5

Check by substituting 5 for b
2 (5+3)+2(5)=26
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3 years ago
I need the answer ASAP anyone could help me please
cupoosta [38]

Answer:

Is it the answer is C?

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7 0
3 years ago
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PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198
Elena-2011 [213]

The weight in 1980 is \frac{4k}{5} kilograms

<em><u>Solution:</u></em>

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

<em><u>To find: weight in 1980</u></em>

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

<em><u>The percentage increase is given by formula:</u></em>

\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

<em><u>Substituting the values in formula,</u></em>

25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}

Thus the weight in kilograms in 1980 is \frac{4k}{5}

7 0
3 years ago
Consider the equation 5/3v +4 + 1/3v = 8. What is the resulting equation after the first step in the equation?
Fed [463]
I hope this helps you



5+1/3v=8-4



6/3v=4



2/v=4



v=2/4


v=1/2
4 0
3 years ago
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