To be honest with u I think that u need to multiply 10 times 48.. I think thats it not sure if is the 100% correct answer
Answer:
the solution is A
Step-by-step explanation:
![\sqrt[3]{27a^{3}b^{7} } \\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B3%7Db%5E%7B7%7D%20%20%7D%20%5C%5C)
![\sqrt[3]{(3)^3(a^3)(b^6)b}\\\\3ab^2\sqrt[3]{b}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%283%29%5E3%28a%5E3%29%28b%5E6%29b%7D%5C%5C%5C%5C3ab%5E2%5Csqrt%5B3%5D%7Bb%7D)
Answer:
D is the answer
Step-by-step explanation:
A conservative vector field
has curl
. In this case,
so the vector field is not conservative.
Answer:
y = -18
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
y = 5x - 3
3x - 2y = 27
<u>Step 2: Rewrite systems</u>
- Define: 3x - 2y = 27
- Add 2y on both sides: 3x = 2y + 27
- Divide 3 on both sides: x = 2/3y + 9
<u>Step 3: Redefine</u>
y = 5x - 3
x = 2/3y + 9
<u>Step 4: Solve for </u><em><u>y</u></em>
- Substitute in <em>x</em>: y = 5(2/3y + 9) - 3
- Distribute 5: y = 10/3y + 45 - 3
- Combine like terms: y = 10/3y + 42
- Subtract 10/3y on both sides: -7/3y = 42
- Divide -7/3 on both sides: y = -18
