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____ [38]
3 years ago
9

If 15.5 gallons are $24.16, how much is it for one gallon

Mathematics
1 answer:
nlexa [21]3 years ago
8 0

Answer:

$1.55870968

Step-by-step explanation:

24.16dollars/15.5gallons = 1.55870968dollars/gallon

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How to solve this?someone help me
umka21 [38]

Hope it helps you! ........

5 0
3 years ago
Solve these simultaneous equations. Use any method you want<br> 2x+y=22<br> X-y=5
sveta [45]

Answer:

15 its not 22

Step-by-step explanation:

bec x y is 5 ya

soo 2 x 5 + 5=15

good luck need more

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3 years ago
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Dwayne buys ingredients to make a cake. He buys 1 1/2 pounds of flour, 12 ounces of coconut, and 1 1/4 pounds of sugar. What is
AVprozaik [17]

Answer:

3.05 or 31/2 pounds

56 ounces

Step-by-step explanation:

To find the total weight all the weights have to have the same units of measurements

It is either pounds is converted to ounces or ounces is converted to pounds

1. convert ounces to pound

1 ounce = 0.0625

12 ounces = 0.0625 x 12 = 0.75 pounds or 3/4

add together = 1 1/2 + 3/4 + 1 1/4 = 1\frac{1}{2} + \frac{3}{4}  + 1\frac{1}{4}

2\frac{2 +3 + 1}{4} = 2\frac{6}{4} = 3 1/2

2. 16 ounces = 1 pound

flour = 16 x 1 1/2 = 24

sugar = 16 x 1 1/4 = 20

total = 24 + 20 + 12 = 56 ounces

6 0
3 years ago
Need Help, (Show your work.)<br><br>I don't understand this. ​
trasher [3.6K]

Answer:

  A = 1577.72

Step-by-step explanation:

Put each of the given values in place of the corresponding variable. Use a calculator to evaluate the expression.

  A=P\left(1+\dfrac{r}{n}\right)^{nt}\\\\A=650\left(1+\dfrac{.06}{2}\right)^{2\cdot15}\\\\A=650(1.03^{30})\approx650(2.427262)\\\\A=1577.72

8 0
2 years ago
A rectangular lawn has an area of 140 square yards. It’s length is six less than twice the width. What are the width and length
liq [111]

Answer:

The width is 10 and the length is 14.

Step-by-step explanation:

To draw this conclusion, first use the equation<em> A = lw = 140 .</em>

Remember the length is six less than twice the width, in other words, the length equals 2 time the width minus 6:<em> l = 2w - 6 </em>

Now you want to substitute numbers in:

140 = (2w - 6)(w)

140 = 2w^2 - 6w

2w^2 - 6w -140 = 0

w^2 - 3w - 70 = 0

Factorable by inspection!

(w - 10)(w + 7) = 0

w = 10  

<em>w = -7 (nonsense - ignore) </em>

I = 14

6 0
4 years ago
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