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ollegr [7]
3 years ago
13

What’s the answer??????

Mathematics
1 answer:
Pani-rosa [81]3 years ago
8 0

Answer:

its a i think

Step-by-step explanation:

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Solve graphically. Be sure to check your solution
ella [17]
X+y=7
X-y=3
_____
2x. =10
2x/2=10/2
X=5
3 0
3 years ago
1. What form is the function below written in? *
Crank

Answer:

intercept form

(sometimes called factored form)

Step-by-step explanation:

8 0
3 years ago
1.) Expand and simplify (6x-7)+(x-3)+(4x-5) *<br>a.)11x-5<br>b.)11x-15<br>c.)10x-15<br>d.)10×1
LiRa [457]

Answer:

the answer is b 11x-15

Step-by-step explanation:

your collecting like terms then combining them

7 0
4 years ago
David drops a soccer ball off a building. The building is 75 meters tall.
Nezavi [6.7K]

a) 70.1 m

The ball is moving by uniformly accelerated motion, with constant acceleration g=9.8 m/s^2 (acceleration due to gravity) towards the ground. The height of the ball at time t is given by the equation

h(t)=h_0 - \frac{1}{2}gt^2

where h_0 = 75 m is the height of the ball at time t=0. Substituting t=1 s, we can find the height of the ball 1 seconds after it has been dropped:

h(1 s)=75 m - \frac{1}{2}(9.8 m/s^2)(1 s)^2=70.1 m

b) 3.9 s

We can still use the same equation we used in the previous part of the problem:

h(t)=h_0 - \frac{1}{2}gt^2

This time, we want to find the time t at which the ball hits the ground, which means the time t at which h(t)=0. So we have

0=h_0 - \frac{1}{2}gt^2

And solving for t we find

t=\sqrt{\frac{2h_0}{g}}=\sqrt{\frac{2(75 m)}{9.8 m/s^2}}=3.9 s

8 0
4 years ago
A) __m=10km 25m =___km
timurjin [86]

Answer:

a) 10,025 m = 10km 25m = 10.025 km

b) 1,500 m = 1 km 500 m = 1.5 km

4 0
3 years ago
Read 2 more answers
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