20 points!!!!

Mathematics

1 answer:

jenyasd209 [6]3 years ago

6 0

Answer: b or a

Step-by-step explanation:

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A committee of 5 people is to be chosen from a group of 8 women and 10 men. How many diffferent committees are possible? How man

Jet001 [13]

A) 5 to be chosen among a Total : 10 Men + 8 Women

¹⁸C₅ = (18!)/(5!)(13!) = 8,568 groups of five

b) A must to have men and women. If so we have to deduct all groups of 5 that are all men and all group of 5 that are all women
Groups of 5 with only men: ¹⁰C₅ = 252
Groups of 5 with only women: ⁸C₅ = 56

So number of committees of 5 men and women mixed =
8568 - 252 - 56 = 8,260 committees

c) 3 Women and 2 Men:

⁸C₃ x ¹⁰C₂ = 2,520 groups of 3 W and 2 M

d) More women than men, it means:
3 W + 2 M OR (we have found it in c) = 2,520)
4 W + 1 M OR ⁸C₄ x ¹⁰C₁ →→→→ = 700
5 W + 0 M OR ⁸C₅ x ¹⁰C₀ →→→→ = 56

Total where W>M = 3,276 groups of 5 where women are at least 3

3 0

3 years ago

What is the range of y = (x - 5)^2 – 1?

Setler79 [48]

1. The graph is a parabola.

2. The parabola opens up, because there's no negative number in front of $(x-5)^2$ .