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Sedaia [141]
3 years ago
5

If a runner runs at a constant rate of 6 miles per hour how much time would it take for her to run 9 miles

Mathematics
2 answers:
wel3 years ago
8 0

Answer:

1.5 hours

Step-by-step explanation:

Neko [114]3 years ago
5 0

Answer:

1  1/2

Step-by-step explanation:

divide 9 by 6 (because its 6 miles per hour) you get 1  1/2. so it would be 1  1/2 hours or 1/5 hours

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Pls answer this question im confused
expeople1 [14]

Answer:

D) 0.05, 0.0516, 16%, \frac{5}{16}, 5.16

Step-by-step explanation:

Convert the factions and percentages to decimals to solve the problem quickly. Then, put them least to greatest.

Example: \frac{5}{16} is 0.3125 and 16% is 0.16.

6 0
3 years ago
40.32 is 76.8% of what number
Anna71 [15]
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</span>
3 0
3 years ago
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Lou eats 6/8 of pizza. what fraction of the pizza is left over?
AfilCa [17]
So, if the pizza is cut into 8 slices that would mean we just have to subtract 6 - 8 = 2 so your answer is 2/8 of the pizza is left

Hope this helped!
4 0
3 years ago
Simply the expression using a like term 8y+2y+6y
expeople1 [14]
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4 0
3 years ago
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Let f = {(x, y) ∈ R × R | xy = 2x + y + 1} There is at least one x ∈ R with no y ∈ R. Find all such problematic x ∈ R. Then rest
loris [4]

Answer:

Problematic x is x = 1

Step-by-step explanation:

Equation:

xy= 2x + y + 1

xy - y = 2x + 1

y(x-1) = 2x + 1

y = (2x+1)/(x-1)

The problematic x is such that when the denominator of the function is 0

x - 1 = 0

x = 1 (the problematic x)

So the domain of f is: x is the subset of R (real number) with the exception of x =/ 1 (x not equal to 1)

To prove this, we can plot the graph and in the graph we can see that as the value of x approaches from negative values to 1, y value will approaches negative infinity, and as the value of x approaches from large positive numbers, y value approaches infinity.

In other words, we'll see an assymptote at x=1

To prove that it is a function, we can do vertical line test by drawing vertical lines accross the graph. We'll see that each line crosses the equation line once hence proving the equation as a function

5 0
3 years ago
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