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3 years ago

Lori had $126.89 in her bank account. She deposited $21.49 into it and then wrote a check for her car repairs for $156.61.

Mathematics

1 answer:

alexandr402 [8]3 years ago

6 0

Answer:

None of the above, it would be -8.23

Step-by-step explanation:

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It is known as a <span>Translation</span>

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elena-s [515]

Answer:

$-1\frac{5}{2}-\frac{7}{12}=\frac{-49}{12}$

Step-by-step explanation:

Given : Expression $-1\frac{5}{2}-\frac{7}{12}$

To find : Subtract the expression ?

Solution :

Step 1 - Write the expression,

$-1\frac{5}{2}-\frac{7}{12}$

Step 2 - Write mixed form into proper form,

$-1\frac{5}{2}-\frac{7}{12}=-\frac{7}{2}-\frac{7}{12}$

Step 3 - Take least common denominator,

$-1\frac{5}{2}-\frac{7}{12}=\frac{-42-7}{12}$

Step 4 - Solve,

$-1\frac{5}{2}-\frac{7}{12}=\frac{-49}{12}$

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4 years ago

The amount of revenue in dollars, y, that Makayla receives from selling x posters is given by the equation y = 3x. The cost of p

d1i1m1o1n [39]

Answer:

75 posters

Step-by-step explanation:

Given

$y = 3x$ ---- Revenue

$y = \frac{x}{3} + 200$ --Cost of production

Required

Determine the number of posters that when cost equals revenue

To do this, we simply equate both equations

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Collect like terms.

$3x - \frac{x}{3} = 200$

Multiply through by 3

$3(3x - \frac{x}{3}) = 200*3$

$9x - x = 600$

$8x = 600$

Divide both sides by 8

$\frac{8x}{8} = \frac{600}{8}$

$x = \frac{600}{8}$

$x = 75$

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3 years ago

the value in dollars, v (x), of a certIN TRUCK AFTER X years is represented by the equation v(x) = 32.500 (0.92)^X. theo the nea

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Answer:

Answer: The truck is worth of $27508 after 2 years.

Step-by-step explanation:

Since we have given that

The value in dollars v(x), of a certain truck after x years is represented by the equation :

We need to find the price of the truck after 2 years,

so, x= 2

So, we put the value of x = 2 in the above equation:

Hence, the truck is worth of $27508 after 2 years.

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3 years ago

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Answer:

y = (x - 2)² - 4

Step-by-step explanation:

I graphed the points on the graph below and found a function that had those points as solutions.

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