The answer would be none of these
The rate a which the surface area, S, decreases is

The surface area is
S = 4πr²
where r = the radius at time t.
Therefore

When r = 3 cm, obtain
![\frac{dr}{dt}]_{r=3} = - \frac{1}{3} \, cm/s](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdr%7D%7Bdt%7D%5D_%7Br%3D3%7D%20%3D%20-%20%5Cfrac%7B1%7D%7B3%7D%20%5C%2C%20cm%2Fs%20%20)
Answer: -1/3 cm/s (or -0.333 cm/s)
Answer:
The length and width are 11ft and 5ft respectively
Step-by-step explanation:
let the
length = L
Width = W
Area = LW = 55
The length is nine feet less than four times the width
L = 4W - 9
W (4W - 9) = 55
4W^2 - 9W -55 = 0
4W^2 - 20W + 11W - 55 = 0
4W(W - 5) + 11(W - 5) = 0
(W - 5)(4W + 11) = 0
W - 5 = 0 , 4W + 11=0
W = 5 or - 11/4
since the width cannot be negative, W = 5
LW = 55
L = 55/5
L = 11
The length and width are 11ft and 5ft respectively.
Answer is d=2 1/3
Because find area of a triangle =1/2×b×h
U will get 7/3
Answer: 2
8 to the power of 1/3 is 2.
Step-by-step explanation: