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pochemuha
3 years ago
13

If B equals 3 then B -2 is equivalent to what

Mathematics
1 answer:
finlep [7]3 years ago
5 0
B = 3
B - 2 = 3 - 2
3 - 2 = 1

B - 2 is equivalent to 1
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Which number line represents the solution set for the inequality 3(8-4x) < 6(x - 5)?
STatiana [176]

Answer:

x>3

Step-by-step explanation:

We are given with the inequation 3(8-4x) < 6(x - 5)

Dividing both sides in the above in equation by 3 we get

(8-4x)<2(x-5)

Distributing 2 over (x-5)

(8-4x)<2x-10

8-4x<2x-10

adding 10 and 4x on both hand sides we get

8+10<2x+4x

18<6x

Dividing both sides by 6 we get

3<x

Hence the solution to the given in equation is x>3

7 0
3 years ago
A flat rectangular piece of aluminum has a perimeter of 70 inches. The length is 11 inches longer than the width. Find the width
rodikova [14]

perimeter = 2L +2w

L = w+11

70 = 2(w+11) +2w

70 = 2w+22+2w

70= 4w + 22

48 = 4w

w=48/4 = 12

width = 12

length = 12+11 = 23

2x12 = 24

2x23 = 46

46+24 = 40

 length = 23 inches, width = 12 inches

Answer is D

5 0
3 years ago
Read 2 more answers
A summer camp had
trapecia [35]

The equation that relates the number of campers this year to the number of campers last year is c = 440 / 1.10

The number of campers last year is 400.

<h3>What are percentages?</h3>

Percentage can be described as a fraction out of an amount that is usually expressed as a number out of hundred. Percentages are used to measure frequency.

<h3>How many campers attended last year?</h3>

The number of campers last year = number of campers this year / (1 + percentage increase)

440 / 1.1 = 400

To learn more about percentages, please check: brainly.com/question/25764815

3 0
2 years ago
Solve the given differential equation by using an appropriate substitution. The DE is a Bernoulli equation.
Mama L [17]

Multiplying both sides by y^2 gives

xy^2\dfrac{\mathrm dy}{\mathrm dx}+y^3=1

so that substituting v=y^3 and hence \frac{\mathrm dv}{\mathrm dv}=3y^2\frac{\mathrm dy}{\mathrm dx} gives the linear ODE,

\dfrac x3\dfrac{\mathrm dv}{\mathrm dx}+v=1

Now multiply both sides by 3x^2 to get

x^3\dfrac{\mathrm dv}{\mathrm dx}+3x^2v=3x^2

so that the left side condenses into the derivative of a product.

\dfrac{\mathrm d}{\mathrm dx}[x^3v]=3x^2

Integrate both sides, then solve for v, then for y:

x^3v=\displaystyle\int3x^2\,\mathrm dx

x^3v=x^3+C

v=1+\dfrac C{x^3}

y^3=1+\dfrac C{x^3}

\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}

6 0
3 years ago
Plz help look at the Picture thanks so much for the Help
Kisachek [45]
The amount of the markup is 20% of 25.15

EQUATION 1: 20/100 * 25.15

ANSWER TO EQUATION 1: 503/100

Then we have divide 503 and 100

EQUATION 2: 503/100

FINAL ANSWER: $5.03

The amount of the markup is $5.03
3 0
3 years ago
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