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4 years ago

Name the coordinate of P(-5, 8) under a translation along the (x+2, y -1)

1 answer:

5 0

(-3, 7)

Explanation: the point (-5,8) moves to the left (x axis) 2 points and down (y axis) 1 point. Thus -5 + 2 = -3 and 8 - 1 = 7, so the answer is (-3, 7)

You might be interested in

Find the coefficient of x^2 in the expansion of (2x-1)^7

kvv77 [185]

(2x-1)^7
=(2x)^7+7(2x)^6(-1)+21(2x)^5(-1)^2+35(2x)^4(-1)^3+35(2x)^3(-1)^4+21(2x)(-1)^5+7(2x)(-1)^6+(-1)^7
=128x^7+7(64x^6)(-1)+21(32x^5)+35(16x^4)(-1)+35(8x^3)+21(4x^2)(-1)+14x-1
=128x^7-7(64x^6)+672x^5-35(16x^4)+280x^3-21(4x^2)+14x-1
=128x^7-448x^6+672x^5-560x^4+280x^3-84x^2+14x-1
The coefficient of x^2 is -84

7 0

3 years ago

If -8x + 8 = 51, what does x equal?

ladessa [460]

Step-by-step explanation:

Given

- 8x + 8 = 51

- 8x = 51 - 8

- 8x = 43

x = - 43 / 8

Hope it will help :)❤

8 0

3 years ago

Read 2 more answers

Complete the table by converting each decimal to a fraction.

AlekseyPX

if you've read those links already, you'd know what we're doing here.

we'll move the repeating part to the left-side of the dot, by multiplying by "1" and as many zeros as needed, or 10 at some power pretty much.

on 0.13 we need 100 to get 13.13.... and on 0.1234, we need 10000 to get 1234.1234....

$\bf 0.\overline{13}~\hspace{10em}x=0.\overline{13}
\\\\[-0.35em]
~\dotfill\\\\
\begin{array}{|lll|ll}
\cline{1-3}
&&\\
100\cdot 0.\overline{13}& = & 13.\overline{13}\\
100\cdot x&& 13 + 0.\overline{13}\\
100x&&13+x
\\&&\\
\cline{1-3}
\end{array}\implies \begin{array}{llll}
100x=13+x\implies 99x=13
\\\\
x=\cfrac{13}{99}
\end{array}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
0.\overline{1234}~\hspace{10em}x=0.\overline{1234}
\\\\[-0.35em]
~\dotfill$

$\bf \begin{array}{|ccc|ll}
\cline{1-3}
&&\\
10000\cdot 0.\overline{1234}&=&1234.\overline{1234}\\
10000\cdot x&=&1234+0.\overline{1234}\\
10000x&=&1234+x
\\&&\\
\cline{1-3}
\end{array}\implies \begin{array}{llll}
10000x=1234+x
\\\\
9999x=1234\implies x=\cfrac{1234}{9999}
\end{array}$

7 0

3 years ago

Read 2 more answers

13) Which fraction needs the fewest parts to mark 1 whole? <br>1/10,1/5,1/7,1/9

ad-work [718]

Answer:

1/5

Step-by-step explanation:

it's denominator is 5, so it needs 5 parts to make a whole

3 0

3 years ago

State the vertical asymptote of the rational function. f(x) =((x-9)(x+7))/(x^2-4)

Lubov Fominskaja [6]

$D:x^2-4\not=0\\
D:x^2\not=4\\
D:x\not=-2 \wedge x\not =2\\\\
\displaystyle
\lim_{x\to-2^-}\dfrac{(x-9)(x+7)}{x^2-4}=\\
\dfrac{(-2-9)(-2+7)}{(-2^-)^2-4}=\dfrac{-11\cdot5}{4^+-4}=\dfrac{-55}{0^+}=-55\cdot\infty=-\infty\\
\dfrac{(-2-9)(-2+7)}{(-2^+)^2-4}=\dfrac{-11\cdot5}{4^--4}=\dfrac{-55}{0^-}=-55\cdot(-\infty)=\infty
$

$\displaystyle
\lim_{x\to2^-}\dfrac{(x-9)(x+7)}{x^2-4}=\\
\dfrac{(2-9)(2+7)}{(2^-)^2-4}=\dfrac{-7\cdot9}{4^--4}=\dfrac{-63}{0^-}=-63\cdot(-\infty)=\infty\\
\dfrac{(2-9)(2+7)}{(2^+)^2-4}=\dfrac{-7\cdot9}{4^+-4}=\dfrac{-63}{0^+}=-63\cdot\infty=-\infty\\$

So, the vertical asymptotes are $x=\pm 2$

5 0

4 years ago

Read 2 more answers