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Tatiana [17]
3 years ago
10

Anyone mind helping me out?

Mathematics
1 answer:
Igoryamba3 years ago
4 0

Answer:

611 square miles

Step-by-step explanation:

Area of triangle = (1/2)*a*b*sinC (formula when u are not given the height of the triangle, but u are given with the angle.)

= (1/2)*30*47*sin(60°)

= 610.54 square miles (2 d.p)

≈611 square miles (rounded to nearest mile)

:)

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$11.49 for 3 packages​
IgorLugansk [536]

Answer:

34.47

Step-by-step explanation:

multiply $11.49 by 3

6 0
3 years ago
The variables x and y are proportional. Use the values to find the constant of proportionality. Then write an equation that rela
Luba_88 [7]

<u>Answer</u>:

equation: y = 24x

Step-by-step explanation:

if y and x is proportional,

y = kx

72 = k * 3

k = 24

→ Here the constant if 24

so the equation that relates x and y :

y = 24x

8 0
3 years ago
a block of apartments have 20 floors with 20 windows on each floor how many windows does the block have all together​
bija089 [108]

Answer:

There are 420 windows.

Step-by-step explanation:

If the ground floor is part of the 20 =>

20.20=400

There are 400 windows.

If the ground floor is not part of the 20=>

20.20+20=420

There are 420 windows.

4 0
3 years ago
In △ABC, points M and P are points on sides AC and BC respectively. Find the area of △MPC, if BM∩AP=O, AAOM=45 dm2, ABOP=15 dm2,
aniked [119]

First calculate the Area of MOP by using congruent altitudes.

(Area MOP)/(Area AOM) = PO/OA = (Area BOP)/(Area AOB)

Area MOP = (Area AOM)*(Area BOP)/(Area AOB) = (45)*(15/75) = 9.

Now, let Area CMP = x. And use two sets of triangles with congruent altitudes.

(Area CMP)/(Area BMP) = x/(9+15) = x/24 = (CP)/(BP).

(Area CAP)/(Area BAP) = (x+54)/90 = (CP)/(BP)

So,

(Area CMP)/(Area BMP) = (Area CAP)/(Area BAP)

or

x/24 = (x+54)/90

90x = 24 (x+54) = 24x + 1296

66x = 1296

x = 19 \frac{7}{11}

8 0
4 years ago
Rewrite the following arguments using letters to represent the terms, reduce the number of terms and put the arguments in to sta
Gwar [14]

Answer:

P2 affirms P1 and the conclusion is in the same direction.

P1--->P2--->C

This argument is valid.

Step-by-step explanation: using the syllogism rules.

Premises 1 (P1) = Some foreign emissaries are persons without diplomatic immunity,

Premises 2 (P2) = so some persons invulnerable to arrest and prosecution are foreign emissaries

Conclusion (C) = because no persons with diplomatic immunity are persons vulnerable to arrest and prosecution.

From the argument:

P1 uses "some", that means it's not "all" foreign emissaries person that does not have diplomatic immunity. This means that some other foreign emissaries have diplomatic immunity

P2 uses "some", that means it's affirms to that part of P1 which states that some foreign emissaries have diplomatic immunity.

The conclusion is valid because the part of P2 which states that some foreign emissaries are vulnerable to arrest, which affirms with P1 which states that Some foreign emissaries are persons without diplomatic immunity. That means no persons with diplomatic immunity are persons vulnerable to arrest and prosecution. This conclusion literally means that if you don't have diplomatic immunity, you are vulnerable to arrest and prosecution.

Therefore;

P2 affirms P1 and the conclusion is in the same direction.

P1--->P2--->C

This argument is valid.

5 0
3 years ago
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