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PolarNik [594]
3 years ago
11

I need help solving 6*[(32-8)/4+2] apsp

Mathematics
1 answer:
nlexa [21]3 years ago
5 0

Answer:

24

Step-by-step explanation:

6*[(32-8)/(4+2)]

| |

24 6

6* [24/6]

|

4

6*4 = 24

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Evaluate the expression when x=-6.<br> x² + 5x-5
Rus_ich [418]

Answer:

1

Step-by-step explanation:

x² + 5x-5

Let x = -6

(-6)^2 + 5(-6) -5

36 -30 -5

6-5

1

6 0
3 years ago
Wal-Mart is selling 12 highligters for $5.47. What is the unit price of the highlighters? (round the price to the nearest hundre
BaLLatris [955]

To be able to quickly solve this, we can temporarily make 5.47 into 547

Now, we can divide 547 by 12.

547 / 12 = 45.5

Now, we can round up from 45.5 to get 46.

However, we originally moved our decimal 2 places over, so now we must move it 2 places again.

46 ⇒ 0.46

The correct answer is $0.46

4 0
3 years ago
Find two consecutive integers whose <br> Sum is 93.
Alla [95]

Answer:

46 and 47.

Step-by-step explanation:

If x is one of the integers then the other is x+1.

x + x + 1 = 93

2x = 92

x = 46.

6 0
3 years ago
Read 2 more answers
X^2+3x^3+27-x <br> Arrange the polynomial so that the powers of x are in decending order
Monica [59]

Answer:

3x^3 + x^2 -x + 27

8 0
3 years ago
Which table represents a quadratic relationship?
svp [43]

In each case, the x-values are equally-spaced. Thus looking at second differences will tell you if the relation is quadratic. If the second differences are non-zero and constant, then the values have a quadratic relationship.

A. First differences are 2-4 = -2, 1-2 = -1, 0.5-1 = -0.5. Second differences are -1-(-2) = 1, -0.5-(-1) = 0.5. Since 1 ≠ 0.5, this relation is not quadratic. (It is exponential with a base of 1/2.)

B. First differences are 128-135 = -7, 105-128 = -23, 72-105 = -33. Second differences are -23-(-7) = -16, -33-(-23)=-10. Since -16 ≠ -10, this relation is not quadratic. (It is cubic, since 3rd differences are constant at +4.)

C. First differences are -23.2-(-23.4) = 0.2, -23.0-(-23.2) = 0.2, -22.8-(-23.0) = 0.2. Second differences are zero, so this is not a quadratic relation. (It is linear, with a slope of 0.2.)

D. First differences are 56-90 = -34, 26-56 = -30, 0-26 = -26. Second differences are -30-(-34) = 4, -26-(-30) = 4. These are constant (=4), so the relation is quadratic.

The appropriate choice is ...

... D. x -1 0 1 2 3 4

... f(x) 90 56 26 0 -22 -40

4 0
3 years ago
Read 2 more answers
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