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PolarNik [594]
3 years ago
11

I need help solving 6*[(32-8)/4+2] apsp

Mathematics
1 answer:
nlexa [21]3 years ago
5 0

Answer:

24

Step-by-step explanation:

6*[(32-8)/(4+2)]

| |

24 6

6* [24/6]

|

4

6*4 = 24

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Tom and Jerry leave from the same place in opposite directions. Tom drives 38mph. Jerry drives 50mph. In how many hours are they
devlian [24]

Answer:

Both Tom and Jerry will apart 176 miles in 2 hours .

Step-by-step explanation:

Given as:

Tom and Jerry moves in opposite direction

The speed of Tom = 38 mph

The speed of Jerry = 50 mph

Let The distance cover by Tom = x mile

The  distance cover by Tom = ( 176 - x ) miles

Time taken by both are same = T hour

\textrm(Time) = \dfrac{\textrm(Distance)}{\textrm(Speed)}

Or, Time taken by Tom

T =  \frac{x}{38}     ... 1

∴ x = 38 T  

And Time taken by Jerry

 \textrm(T) = \dfrac{\textrm(Distance)}{\textrm(Speed)}

Or, T =  \frac{176 - x}{50}  

So , put the value of T from 1

\frac{x}{38}  =  \frac{176 - x}{50}  

Or, 50 × x = ( 176 - x ) × 38

So 50 x + 38 x = 6688

Or, 88 x = 6688

∴   x = \frac{6688}{88} = 76 mile

So, From, eq 1

T =  \frac{x}{38}

or, T =  \frac{76}{38}  = 2 hours

Hence both Tom and Jerry will apart 176 miles in 2 hours . Answer

7 0
4 years ago
He perimeter of this pentagon is 280 cm. find the lengths of the sides.
olga2289 [7]
IF the pentagon has 5 equal sides then each side is
280 / 5 which equals 56 cm


3 0
4 years ago
The base of a right rectangular prism has an area of 84.6 square centimeters and a height of 7 centimeters. What is the volume,
AlladinOne [14]

Answer:

The volume of the right rectangular prism is  592.2cm³

Step-by-step explanation:

To calculate the volume of a rectangular prism we have to multiply the area of ​​the base by the height

a = area of the base = 84.6cm²

h = height = 7cm

v = volume

v = a * h

v = 84.6cm² * 7cm

v = 592.2cm³

The volume of the right rectangular prism is  592.2cm³

6 0
3 years ago
15-18, use the properties of the exponents to write an equivalent expression for each given expression.
Leto [7]

15.

( {4}^{4} ) {}^{3}

=  {4}^{4 \times 3}

=  {4}^{12}

= 16777216

___________________________________________

16.

\frac{ {3}^{12} }{ {3}^{3} }

=  {3}^{12 - 3}

=  {3}^{9}

= 19683

___________________________________________

17.

{4}^{5}  \times  {4}^{2}

=  {4}^{(5 + 2)}

=  {4}^{7}

= 16384

___________________________________________

18.

{6}^{4}  \times  {2}^{4}

=  ({6 \times 2})^{4}

=  {12}^{4}

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6 0
3 years ago
F(x)=x2-10 and g(x)=11-x find (f-g)(x)(f-g)(10) and (f/g)(x) if they exist
tester [92]

Answer:

(f - g)(x) = x^2 + x-21

(f - g)(10) = 89

(f/g)(x) = \frac{x^2 - 10}{11 - x}

Step-by-step explanation:

Given

f(x) = x^2 - 10

g(x) = 11  - x

Solving (1): (f-g)(x)

(f - g)(x) = f(x) - g(x)

Substitute values for f(x) and g(x)

(f - g)(x) = x^2 - 10 - (11 - x)

Open Bracket

(f - g)(x) = x^2 - 10 - 11 + x

(f - g)(x) = x^2 -21 + x

Reorder

(f - g)(x) = x^2 + x-21

Solving (2): (f-g)(10)

In (1)

(f - g)(x) = x^2 + x-21

So:

(f - g)(10) = 10^2 + 10-21

(f - g)(10) = 100 + 10-21

(f - g)(10) = 89

Solving (3): (f/g)(x)

(f/g)(x) = \frac{f(x)}{g(x)}

Substitute values for f(x) and g(x)

(f/g)(x) = \frac{x^2 - 10}{11 - x}

6 0
3 years ago
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