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3 years ago

I need help solving 6*[(32-8)/4+2] apsp

Mathematics

1 answer:

nlexa [21]3 years ago

5 0

Answer:

Step-by-step explanation:

6*[(32-8)/(4+2)]

| |

24 6

6* [24/6]

6*4 = 24

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Tom and Jerry leave from the same place in opposite directions. Tom drives 38mph. Jerry drives 50mph. In how many hours are they

devlian [24]

Answer:

Both Tom and Jerry will apart 176 miles in 2 hours .

Step-by-step explanation:

Given as:

Tom and Jerry moves in opposite direction

The speed of Tom = 38 mph

The speed of Jerry = 50 mph

Let The distance cover by Tom = x mile

The distance cover by Tom = ( 176 - x ) miles

Time taken by both are same = T hour

$\textrm(Time) = \dfrac{\textrm(Distance)}{\textrm(Speed)}$

Or, Time taken by Tom

T = $\frac{x}{38}$ ... 1

∴ x = 38 T

And Time taken by Jerry

$\textrm(T) = \dfrac{\textrm(Distance)}{\textrm(Speed)}$

Or, T = $\frac{176 - x}{50}$

So , put the value of T from 1

$\frac{x}{38}$ = $\frac{176 - x}{50}$

Or, 50 × x = ( 176 - x ) × 38

So 50 x + 38 x = 6688

Or, 88 x = 6688

∴ x = $\frac{6688}{88}$ = 76 mile

So, From, eq 1

T = $\frac{x}{38}$

or, T = $\frac{76}{38}$ = 2 hours

Hence both Tom and Jerry will apart 176 miles in 2 hours . Answer

7 0

4 years ago

He perimeter of this pentagon is 280 cm. find the lengths of the sides.

olga2289 [7]

IF the pentagon has 5 equal sides then each side is
280 / 5 which equals 56 cm

3 0

4 years ago

The base of a right rectangular prism has an area of 84.6 square centimeters and a height of 7 centimeters. What is the volume,

AlladinOne [14]

Answer:

The volume of the right rectangular prism is 592.2cm³

Step-by-step explanation:

To calculate the volume of a rectangular prism we have to multiply the area of the base by the height

a = area of the base = 84.6cm²

h = height = 7cm

v = volume

v = a * h

v = 84.6cm² * 7cm

v = 592.2cm³

The volume of the right rectangular prism is 592.2cm³

6 0

3 years ago

15-18, use the properties of the exponents to write an equivalent expression for each given expression.

Leto [7]

15.

$( {4}^{4} ) {}^{3}$

$= {4}^{4 \times 3}$

$= {4}^{12}$

$= 16777216$

___________________________________________

16.

$\frac{ {3}^{12} }{ {3}^{3} }$

$= {3}^{12 - 3}$

$= {3}^{9}$

$= 19683$

___________________________________________

17.

${4}^{5} \times {4}^{2}$

$= {4}^{(5 + 2)}$

$= {4}^{7}$

$= 16384$

___________________________________________

18.

${6}^{4} \times {2}^{4}$

$= ({6 \times 2})^{4}$

$= {12}^{4}$

$= 20736$

6 0

3 years ago

F(x)=x2-10 and g(x)=11-x find (f-g)(x)(f-g)(10) and (f/g)(x) if they exist

tester [92]

Answer:

$(f - g)(x) = x^2 + x-21$

$(f - g)(10) = 89$

$(f/g)(x) = \frac{x^2 - 10}{11 - x}$

Step-by-step explanation:

Given

$f(x) = x^2 - 10$

$g(x) = 11 - x$

Solving (1): (f-g)(x)

$(f - g)(x) = f(x) - g(x)$

Substitute values for f(x) and g(x)

$(f - g)(x) = x^2 - 10 - (11 - x)$

Open Bracket

$(f - g)(x) = x^2 - 10 - 11 + x$

$(f - g)(x) = x^2 -21 + x$

Reorder

$(f - g)(x) = x^2 + x-21$

Solving (2): (f-g)(10)

In (1)

$(f - g)(x) = x^2 + x-21$

So:

$(f - g)(10) = 10^2 + 10-21$

$(f - g)(10) = 100 + 10-21$

$(f - g)(10) = 89$

Solving (3): (f/g)(x)

$(f/g)(x) = \frac{f(x)}{g(x)}$

Substitute values for f(x) and g(x)

$(f/g)(x) = \frac{x^2 - 10}{11 - x}$

6 0

3 years ago