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2 years ago

find the circumference of a circle that has an area of 452.16 square meters. (Use 3.1416 as the value of π.)

1 answer:

3 0

(1) circumference of a circle = 2π.R
(2) area of a circle = π.R²

Area = 452.16 m² (given), so we can calculate the radius:
452.16 = π.R²
452.16/π = R²

143.92 = R² → R =√143.92 ≈ 12 m
Having R = 12, now we can calculate the circumference :

circumference of a circle = 2π.R = 2.π.12 = 75.41 m

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Vesnalui [34]

Answer:

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Step-by-step explanation:

10 + 25a = 75

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- 6 * 1/3=?please type the equation and simplify if possible

rosijanka [135]

We have to simplify this as a product of fractions. Notice that the 6 has a negative sign, therefore, the result will be negative. We have then:

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11 months ago

A die is rolled. What is the probability that the number is a factor of 6 or more than 2? Does this scenario represent mutually

goblinko [34]

Factors of 6 are : 1,2,3 and 6.

Let us find probability of getting the number that is a factor of 6.

$P(\text{ The number is a factor of 6})=\frac{4}{6} =\frac{2}{3}$

Now let us find probability of getting a number more than 2 (3,4,5,6).

$P(\text{ The number is a greater than 2})=\frac{4}{6} =\frac{2}{3}$

We can see that these two events are mutually inclusive events. We can find probability of mutually inclusive events by formula $P(\text{X or Y})=P(X)+P(Y)-P(\text{X and Y})$ .

$P(\text{ The number is a factor of 6 and greater than 2})=\frac{2}{6} =\frac{1}{3}$

Now we will find probability of getting the number is a factor of 6 or more than 2 using above formula.

$P(\text{ The number is a factor of 6 or greater than 2})=\frac{2}{3} +\frac{2}{3}-\frac{1}{3}$

$P(\text{ The number is a factor of 6 or greater than 2})= \frac{4}{3}-\frac{1}{3}=\frac{3}{3}=1$

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2 years ago

Solve the equation y. 6=2(y+2)

atroni [7]

Answer:

y = 1

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

6-(2*(y+2))=0

Step by step solution :

Equation at the end of step 1 :

6 - 2 • (y + 2) = 0

Pulling out like terms :

3.1 Pull out like factors :

2 - 2y = -2 • (y - 1)

Equation at the end of step 3 :

-2 • (y - 1) = 0

Equations which are never true :

4.1 Solve : -2 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

4.2 Solve : y-1 = 0

Add 1 to both sides of the equation :

y = 1

One solution was found :

y = 1

Processing ends successfully

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