The answer is 1.28 because you add 2.37+35 then subtract that from $5
Answer:
Approximately Normal
Step-by-step explanation:
Since the population is normally distributed, the sampling distribution of the sample mean will also be normally distributed, even when the sample size is small.
I'll solve 21, and you then should be able to solve the rest on your own!
Since ADC is 135, that means that that whole angle is 135 degrees. In addition, since angles ADB and BDC add up to ADC, we get ADB+BDC=ADC=135=11x+9+7x=18x+9. Subtracting 9 from both sides, we get 126=18x. Dividing both sides by 18, we get x=7. Plugging that into 11x+9=BDC, we get 11*7+9=77+9=86
Answer:
800 bacteria
Step-by-step explanation:
Answer of this question depend upon number of hours at the end of day
Let Take Full Day of 24 hrs
Colby bacteria will doubled 12 times ( doubled once in 2hrs => 24/2 = 12)
Colby bacteria at end of day = 50 * 2¹²
Jaquan bacteria will doubled 8 times ( doubled once in 3hrs => 24/3 = 8)
Let say Jaquan bacteria at start of Day = J
Jaquan bacteria at end of day = J * 2⁸
Equating Both
J * 2⁸ = 50 * 2¹²
=> J = 50 * 2⁴
=> J = 50 * 16
=> J = 800
Jaquan will start with 800 Bacteria
Negative. It’s the only one that makes since. ( probably)
