Answer: UV = 52
Concept:
Additive property of length, or the segment addition postulate, states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.
Solve:
<u>Given information</u>
TU = 4x
UV = 2x + 14
TV = 7x - 5
<u>Given expression deducted from the additive property of length</u>
TV = TU + UV
<u>Substitute values into the expression</u>
7x - 5 = 4x + 2x + 14
<u>Combine like terms</u>
7x - 5 = 6x + 14
<u />
<u>Subtract 6x on both sides</u>
7x - 5 - 6x = 6x + 14 - 6x
x - 5 = 14
<u>Add 5 on both sides</u>
x - 5 + 5 = 14 + 5
x = 19
<u>Find UV by substituting the value of x</u>
UV = 2x + 14 = 2 (19) + 14 = 
Hope this helps!! :)
Please let me know if you have any questions
F^-1(x) should be the answer.
Answer:
83 due to the lack of explanation
Step-by-step explanation:
Prime numbers are those numbers which have only two factors, 1 and the number itself . For e.g. 3,5,7,11 etc are all prime numbers.
Between 110 and 130 we have a total of two prime numbers which are 113 and 127, since both have only two factors .
And sum of 113 and 127 is

So the required answer is 240 .
It's asking how far horizontally from the starting point which means that y, the height in meters is 0.
set 0 = -0.06x^2 + 10.1x + 5 and solve for x using the quadratic formula
-b +-

/ 2a
-10.1 +-

/ 2(-0.06)
you get that x = 168.83 m and -0.49 meters. Since the horizontal distance cant be negative, 168.83m is your answer