Answer:
AC:PC=8:5
Step-by-step explanation:
Draw a vertical line from D perpendicular to AB. Denote D' the intersection with I, and D'' intersection with AB. Consider the right triangle ADD". Realize that the lengths |DD"| and |DD'| are 3:5, which follows from triangles ADD" and MDD' being similar. This means that I bisects the trapezoid's height in a ratio 3:5.
Next, draw a vertical line perpendicular to AB, going through P. Denote P" the intersection of this line with AB, and denote P' the intersection of this line with DC. Observe that because lines CD || AB, the angles <BAC and <ACD are congruent. This implies triangles APP" and CPP' are similar with a side ratio 3:5, i.e., |AP|/|PC|=3/5. Therefore |AC|/|PC|=(|AP|+|PC|)/|PC|=|AP|/|PC|+1 = 8/5
The ratio AC:PC is 8:5
D = 16
you would collect the terms
(9-8)x = 16
1x = 16
x = 16
Your answer goes to 3995.100
So the probablity is desired outcomes divided by total possible outcomes
so assume duncan gets an orange on the first try, that would be 4/9
then carlos picks another fruit, also assuming that duncan got an orange so 5/8
then these are dependant on each other so we multiply
4/9 times 5/8=20/72=10/36=5/18