From the given mean and margin of error, the 99% confidence interval for the mean amount of money spent on lunch per week for all students is:
[$19.5, $22.5].
<h3>How to calculate a confidence interval given the sample mean and the margin of error?</h3>
The confidence interval is given by the sample mean plus/minus the margin of error, hence:
- The lower bound is the sample mean subtracted by the margin of error.
- The upper bound is the sample mean added to the margin of error.
For this problem, we have that:
- The sample mean is of $21.
- The margin of error is of $1.50.
Hence the bounds are given as follows:
- Lower bound: 21 - 1.50 = $19.50.
- Upper bound: 21 + 1.50 = $22.50.
Hence the interval is [$19.50, $22.50].
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Based on the definition of supplementary angles, the measure of both angles are: 80° and 100°.
<h3>What are Supplementary Angles?</h3>
The sum of angles that are supplementary to each other equals 180 degrees.
Let the measure of the supplementary angle be x.
The other angle will be: x + 20.
(x + 20) + x = 180
x + 20 + x = 180
2x + 20 = 180
2x = 180 - 20
2x = 160
x = 160/2
x = 80°
The other angle will be x + 20 = 80 + 20 = 100°.
The measure of the angles are: 80° and 100°.
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Tens=7 Ones=6 Tens=5 Ones=0
Answer:
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