Answer:
Step-by-step explanation:
These problems are based on triangle ratios. You cannot use the Pythagorean theorem to solve them.
The first triangle is a 45 45 90 degree triangle (I'm talking about the angles), and so, the ratio is 1:1:
, so I have to divide the hypotenuse by to get the legs. The hypotenuse is 15
, so that divided by is 15
. X is the same length as y because of the triangle ratio, so both x and y for the first triangle are 15.
The second triangle is a 30 60 90 degree triangle, so the ratio is x:x
:2x. The short leg is 7, so 7 * 2 is the hypotenuse, which is 14. The long leg is 7 * , which is 21. So, x for the second triangle is 14, and y for the second triangle is 21.
Answer:
y = -2x + 7 is the equation if that's what you are asking for.
Answer:
38°
Step-by-step explanation:
The measure of required angle can be obtained by using cosine law.
From the given triangle we find that:
a = 5, b = 3, c = 7,
Since,
cos (A) = (b^2 +c^2 - a^2) /2bc
Therefore,
cos (A) = (3^2 + 7^2 - 5^2) /(2*3*7)
cos (A) = (9 + 49 - 25) /(42)
cos (A) = (33) /(42)
cos (A) = 0.785714286
A = arccos(0.785714286)
A = 38.213210675°
A = 38°
Answer:
y = -6
Step-by-step explanation:
12 (5 + 2y) = 4y- (6 - 9y)
= 60 + 24y = 4y - 6 + 9y
= 60 + 24y = 13y - 6
= 24y - 13y = -6 - 60
= 11y = -66
y = -6
Answer:
Follows are the solution to the given point:
Step-by-step explanation:
In point a:
¬∃y∃xP (x, y)
∀x∀y(>P(x,y))
In point b:
¬∀x∃yP (x, y)
∃x∀y ¬P(x,y)
In point c:
¬∃y(Q(y) ∧ ∀x¬R(x, y)) 
∀y(> Q(y) V ∀ ¬ (¬R(x,y)))
∀y(¬Q(Y)) V ∃xR(x,y) )
In point d:
¬∃y(∃xR(x, y) ∨ ∀xS(x, y))
∀y(∀x>R(x,y)) 
∃x>s(x,y))
In point e:
¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU (x, y, z))
∀y(∃x ∀z)>T(x,y,z) ∀x ∃z> V (x,y,z))
