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Lera25 [3.4K]
3 years ago
8

A seafood company sells salmon and shrimp to local restaurants. The company charges its customers for one price for salmon and a

nother price for shrimp One Restaurant pays $166.83 for 10 lb of salmon and said and cons of shrimp while another pays $143.86 for 5 lb of salmon in 9 lb of shrimp. How much does each Seafood product cost per pound
Mathematics
1 answer:
Romashka [77]3 years ago
3 0

Answer:

salmon per pound is $16.68

shrimp per pound is $6.71

Step-by-step explanation:

166.63/10=16.68

16.68*5=83.04

143.86 -83.04=60.46

60.46/9 = 6.71

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Question: Simplify \frac{\sqrt{8x^2}}{\sqrt{2x}}.

First off, you <em>never</em> want square roots on the bottom of a fraction, so let's multiply both sides by \sqrt{2x} to get rid of it. All we have to do from there is simplify!

\frac{\sqrt{8x^2}}{\sqrt{2x}}*\frac{\sqrt{2x}}{\sqrt{2x}}=\frac{\sqrt{8x^2}*\sqrt{2x}}{2x}}=\frac{\sqrt{16x^3}}{2x}=\frac{4x\sqrt{x}}{2x}=\boxed{2\sqrt{x}}


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3 years ago
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A desk drawer is shaped like a rectangular prism. The height of the drawer is 7 inches. The bottom of the drawer has an area of
Gnom [1K]

Answer:

Volume = 1470\ in^3

Step-by-step explanation:

Given

Height = 7in

Base\ Area = 210in^2

Required

Determine the volume

The volume of the drawer is calculated as:

Volume = Base\ Area * Height

Substitute values for Base Area and Height

Volume = 210\ in^2 * 7in

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3 0
3 years ago
Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1
algol [13]

Find the critical points of f(x,y):

\dfrac{\partial f}{\partial x}=-2x=0\implies x=0

\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12

All three points lie within D, and f takes on values of

\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}

Now check for extrema on the boundary of D. Convert to polar coordinates:

f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t

Find the critical points of g(t):

\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0

\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2

\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi

where n is any integer. There are some redundant critical points, so we'll just consider 0\le t< 2\pi, which gives

t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3

which gives values of

\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}

So altogether, f(x,y) has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

5 0
2 years ago
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