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enot [183]
3 years ago
10

Pythagorean theorem

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
4 0

Answer:

8.7

Step-by-step explanation:

hypotenuse= 14 =c

a=11

b=x

a²+b²=c²

b²=c²-a²

b²=14²-11²

b²= 196-121

b²=75

b=√75=5√3=8.7 rounded to the nearest tenth

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In a quadrilateral ABCD, AB || DC and AD || BC. Find the perimeter of triangle COD if the diagonals of the quadrilateral interse
aalyn [17]
Draw a diagram as shown below.

The diagonals are equal in length. Because AB || DC and AD || BC, the quadrilateral is a square.

Because the diagonals bisect each other at O, therefore
DO = BO = 10.
Likewise,
AO = CO = 10

Because AB = 13, therefore DC = 13.
The perimeter of ΔCOD is CO + CD + DO = 10 + 13 + 10 = 33 in

Answer: 33 in

4 0
4 years ago
A random sample of math majors taking an introductory statistics course were surveyed after completing the final exam. They were
quester [9]

Answer:

E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8

Now we can find the second moment with this formula:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4

The variance would be given by:

Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96

And the deviation would be:

Sd(X) =\sqrt{6.96}= 2.638

Step-by-step explanation:

For this case we have the following distribution given:

X      1      2      7

P(X) 1/5  2/5   2/5

We need to begin finding the mean with this formula:

E(X) = \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8

Now we can find the second moment with this formula:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4

The variance would be given by:

Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96

And the deviation would be:

Sd(X) =\sqrt{6.96}= 2.638

7 0
3 years ago
400 is 10 times as much as
Rzqust [24]
Divide 400 by 10 and you will get 40. It's not hard
8 0
3 years ago
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Answer:

12

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Answer:

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