Answer:
28 units squared
Step-by-step explanation:
It becomes a lot easier if you just try to plot the points on an axis, but i'll try to explain.
A and B are x-intercepts and the bottom two corners of the rectangle. C and D are the top two corners of the rectangle. Like any other case, to find the area, you need just two things:
1) height
2) width
To find the width:
Consider the distance between A and B - the bottom 2 corners. The coordinates are (2,0) and (6,0). Since we are trying to work out the width, just worry about the x-values. So, 6-2 = 4 and that is the width.
To find the height:
We'll take coordinates B and C - the bottom and top right corners of the rectangle. Coordinates are (6,0) and (6,7). Since we are trying to work out the height, just look at the y-values. So, 7 (top corner) - 0 (bottom corner) = 7, which is the height.
To figure out area:
Just multiply width by height, so:
4 x 7 = 28
And the area is 28 units squared. Change the units into whatever unit of measurement they give you (m, cm, mm etc.)
Hope this helped :)
Answer:
Second option,domain: negative infinity, 4 and range, negative infinity, 3
The domain are all the x's that you can input into a function. It looks like the function goes to all x's from negative infinity until it hits positive 4. that's why it is -infinity, 4 for the domain.
The range is all the y's that are outputted. As you can see, the function goes to all y's from negative infinity to 3.
Step-by-step explanation:
Answer:
the difference between a number and 10 simply means ,that number minus 10
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D) 48
2 packs of plates is 48 plates and 3 packs of cups os 48 plates.
Answer:
Points P, Q and R are collinear
Step-by-step explanation:
To prove that two or three points are collinear the slope of any two pairs of point have to be the same
From the given question
AR = AQ = CP = 2 units
BR = BP = CQ = 1 unit
For line AB we have ; AR , BR . hence slope of line = BR / AR = 1/2
For line BC we have ; BP , CP . hence slope of line = CP / BP = 2/1
For Line AC we have ; AQ , CQ . hence slope of line = CQ / AQ = 1/2
slope of Line AB = slope of Line AC hence points P, Q and R are collinear