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Eva8 [605]
3 years ago
8

PLSSSSS HELP DUE IN 3 min Write the equation of the line in fully simplified slope-intercept form.

Mathematics
1 answer:
MissTica3 years ago
6 0
Y=-1/3x-1 I believe is the correct answer
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If you take 5 quizzes and get scores of 95%, 95%, 80%, 85%, and 75%, how would you find your mean quiz score?
avanturin [10]

Answer:

The answer is C.

Step-by-step explanation:

Remember, to find the mean of some scores, you must add all the scores together, then you must divide by the number of scores you added. In this case, you would divide by four, because you had four numbers you added to gether.

4 0
3 years ago
What are the zeros of the function f(x)=x^2-2x-15?
valkas [14]
To find the zeros of this function, we must first set the entire function equal to 0

f(x) = x² - 2x - 15 = 0

Since this is a quadratic function, we must use the quadratic formula, which is:

\frac{-b +/-  \sqrt{b^{2} - 4(a)(c) } }{2a}

Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15

Now let's plug those in:

\frac{-(-2) +/- \sqrt{(-2)^{2} - 4(1)(-15) } }{2(1)}

which simplifies to:

\frac{2 +/- \sqrt{(4 + 60} }{2}

Simplified further:

\frac{2 +/- \sqrt{(64} }{2}
\frac{2 +/- 8 }{2}
And divide it by the 2 on the bottom gives us:

2 +/- 4

2+4 = 6
2-4 = -2

So the zeros of this function are -2 and 6
6 0
3 years ago
Read 2 more answers
Which trip could be modeled by the expression |-6| + |8|?
olga2289 [7]
| -6 | + |8| = 6 + 8 = 14 spaces...so thats gym to school
6 0
4 years ago
Solve for c of the right triangle
Ede4ka [16]
In order to solve this triangle we must use cosine law:
c^{2} = a^{2} + b^{2} - 2ab*cosC

Now let's plug in the values we are given:
c^{2} = 5^{2} + 8^{2} - 2(5)(8) * cos 67
c^{2} = 25 + 64 - 80*cos67
c =  \sqrt{80-cos67}

5 0
4 years ago
Read 2 more answers
In what ways does adding a constant or coefficient to a quadrationc affect the graph
Roman55 [17]
Hope this helps <span>1)   </span><span>Equations with negative values for a</span><span> produce graphs that open down and equations with a positive values for a</span> produce graphs that open up.

<span>2)<span>   </span></span><span>As the absolute value of a gets larger our graphs become more narrow (they shoot towards positive or negative infinity faster). This is more interesting than it might appear. If you consider the second derivative of any quadratic it will be the a</span><span> value. The second derivative represents acceleration, so the larger the a value the faster the increase of velocity and accordingly a quicker progression towards positive or negative infinity. Check this out in graphing calculator, press play to vary the value of a from -20 to 20. Notice that when the value of a approaches zero, the approximates a line, and of course when a is 0 we have the line y</span><span> = 2x</span><span> – 1.</span>

3 0
4 years ago
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