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Shalnov [3]
3 years ago
9

Which expression is the best estimate of 1 1/4 • 3 2/3 ? A) 2 •4 B) 1 •4 C)2•3 D) 1•3

Mathematics
2 answers:
Margarita [4]3 years ago
7 0

Answer:B

Step-by-step explanation:

Estimate it

Levart [38]3 years ago
4 0

Answer:

B) 1·4  

Step-by-step explanation:

When you are estimating with mixed numbers, you should round them off to the closest integers that you can work with in your head.

1¼ is close to 1

3⅔ is close to 4

1¼ × 3⅔ is close to 1 × 4  

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Let u = <-3, -5>, v = <-3, 1>. Find u + v.
Gemiola [76]
U + v =  {-3 + -3,     -5 + 1} =  <span> {-6 ,  -4} 

</span>u + v  =  <span> {-6 ,  -4} </span>
3 0
4 years ago
At a store a shirt has regular price of y dollars. During a sale, the price of the shirt by 40%. The expression 0.60y describes
Alexxx [7]
B i hope you do well fr
6 0
3 years ago
F(x) =10x 5 and g(x) =3x 6 then what is ( f-g)
padilas [110]
(10x 5 - 3x 6)
(50x - 18x)
(f-g) = 32x
7 0
3 years ago
Mai's water bottle had 24 ounces in it. After she drank x
snow_tiger [21]

Answer:

Option B and C is correct

Step-by-step explanation:

<h3><u>Given</u>;</h3>
  • Priya has 5 pencils, each x inches in length.
  • Total length = 34.5 inches.

Now,

5 times x = 34.5

So,

5x = 34.5

34.5 ÷ 5 = x

Thus, 5x = 34.5 and 34.5 ÷ 5 = x are the answer

 

<u>-TheUnknownScientist 72</u>

5 0
2 years ago
An electrical rm manufactures light bulbs that have a life span that is approximately normally distributed. The population stand
stira [4]

Answer:

The 't' test statistic = 1.46 < 1.69

The test of hypothesis is H 0 :μ = 800 is accepted

A sample of 30 bulbs are found came from average µ= 800

Step-by-step explanation:

Step 1:-

Given population of mean μ = 800

given size of small sample n =30

sample standard deviation 'S' = 45

Mean value of the sample χ = 788

Null hypothesis H_{0} =µ  =800

alternative hypothesis  H_{1} = µ ≠ 800

<u>Step 2</u>:-

The 't' test statistic t =  \frac{x-μ}{\frac{sig}{\sqrt{n} } }

                             t = \frac{788-800}{\frac{45}{\sqrt{30} } }

                       t = \frac{12}{8.215} = 1.4607

<u>Step 3</u>:-

The degrees of freedom γ = n-1 = 30-1 =29

From "t" value from table at 0.05 level of significance ( t = 1.69)

The calculated value t = 1.4607 < 1.69

Therefore The null hypothesis H_{0} ' is accepted.

<u>conclusion</u>:-

A sample of 30 bulbs are came found from average µ= 800

7 0
4 years ago
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