Answer: .com — Commercial businesses.
.org — Organizations (generally charitable).
.net — Network organizations.
.gov — U.S. government agencies.
.mil — Military.
.edu — Educational facilities, like universities.
Explanation:
Answer:
See explaination for the code
Explanation:
def wordsOfFrequency(words, freq):
d = {}
res = []
for i in range(len(words)):
if(words[i].lower() in d):
d[words[i].lower()] = d[words[i].lower()] + 1
else:
d[words[i].lower()] = 1
for word in words:
if d[word.lower()]==freq:
res.append(word)
return res
Note:
First a dictionary is created to keep the count of the lowercase form of each word.
Then, using another for loop, each word count is matched with the freq, if it matches, the word is appended to the result list res.
Finally the res list is appended.
Answer:
Top to bottom Answer in order
#1 hardskills
#2 goal
#3 value
#4 soft skills
#5 on the job training
#6 self training
Answer:
This code will no get executed properly.It will give keyerror Brianna.
Explanation:
In this dictionary we defined in the code the there is no key Brianna hence there is no corresponding value to Brianna.So assigning ages['Brianna] to value will obviously give error since there exits no key with this name.So the code will give error.
