Answer:
20.7026
Step-by-step explanation:
Answer: AA similarity theorem.
Step-by-step explanation:
Given : AB ∥ DE
Prove: ΔACB ≈ ΔDCE
We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines. Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA.
Also ∠C ≅ ∠C using the reflexive property.
Therefore by AA similarity theorem , ΔACB ≈ ΔDCE
- AA similarity theorem says that if in two triangles the two pairs of corresponding angles are congruent then the triangles are similar .
Answer:
i actually dont know im so sorry but i will keep trying to find the answer
Answer: 92
Step-by-step explanation:
So 12 +80 = 4(3 + 20) = 92
Answer:
the simplified expression is: 6y-7x
Step-by-step explanation:
-y+7y= 6y
-7x
= 6y-7x
