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Brilliant_brown [7]
3 years ago
6

Which choice is equivalent to the expression below when x  0?

Mathematics
2 answers:
saul85 [17]3 years ago
6 0
\sqrt{18x^3}-\sqrt{9x^3}+3\sqrt{x^3}-\sqrt{2x^3}=\\
3\sqrt{2x^3}-3\sqrt{x^3}+3\sqrt{x^3}-\sqrt{2x^3}=\\
2\sqrt{2x^3}=\\
2x\sqrt{2x}\Rightarrow C
irina [24]3 years ago
4 0
\sqrt{18x^3}-\sqrt{9x^3}+3\sqrt{x^3}-\sqrt{2x^3}\\\\=\sqrt{9x^2\cdot2x}-\sqrt{9x^2\cdot x}+3\sqrt{x^2\cdot x}-\sqrt{x^2\cdot2x}\\\\=3x\sqrt{2x}-3x\sqrt{x}+3x\sqrt{x}-x\sqrt{2x}=2x\sqrt{x}\\\\Answer:C.
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A carpenter took the following measurements: 3.4m, 10.25m, 20.2m, and 19m. How many does the sum of the measurements have ?
Simora [160]
So, I guessing the question is written wrong. The only thing that would make sense is "A carpenter took the following measurements: 3.4m, 10.25m, 20.2m, and 19m. How many SIGNIFICANT FIGURES does the sum of the measurements have?"

1. Add The Measurements
3.4m + 10.25m + 20.2m + 19.0m \\ = 52.85m
52.85 Has 4 Significant Figures, this is the more precise measurement

HOWEVER, the rules of Significant Figures states that when adding we must put our answer in the same amount of decimal places as the least one in our expression. So 3.4has 1 decimal place, 10.25 has 2, 20.2 has 2, and 19.0 has 1. So we must put our answer only to the tens place and not the hundredth as we have it. OUR SIG FIG ANSWER IS;

52.9m
This is considered less precise, for example 19 is just saying approximately 19, while 19.0 says this is exactly 19
8 0
3 years ago
A prism with a base area of 8 cm² and a height of 6 cm is dilated by a factor of 54 .
Alex777 [14]
The volume of the prism is 8*6 = 48
Since we are dilating the prism by a factor of 54
take 54 * 48 = 2592 cm^2
7 0
3 years ago
Sheldon is four years older than his brother Lee.Togethet the boys are at most 26 years old.the inequality c+(c+4) is less or eq
Elden [556K]
C+4 represents Sheldon's age

5+4=9 so Sheldon will be 9 when Lee is 5 

5+9=14 their combined age would be 14

No Lee must be 11 years old exactly to get to 26 because 11+(11+4)=11+15=26 so he must be exactly 11 years old he cannot be older
8 0
4 years ago
Find the area of the regular polygon
olasank [31]

area = 44.0467 \: cm {}^{2}

<h3>step by step explanation </h3>

● area of regular polygon Formulas ,

⟹a = \frac{l^{2}n}{4tan(\frac{\pi }{n)}}

● now finding the area of regular polygon,

⟹\frac{4 {}^{2} \times 8 }{ 4 \: tan \:  \binom{180}{5} }

⟹a =  \frac{128}{4 \times 0.7265}

⟹a = 44.0467 \: cm {}^{2}

Hope it's helps you

4 0
3 years ago
Please help me I am having a hard time with this activity
zysi [14]

Answer:

Step-by-step explanation:

b.

\frac{a^2+6a+9}{a^2-9} *\frac{3a-9}{a+3} \\=\frac{a^2+2*a*3+3^2}{a^2-3^2} *\frac{3(a-3)}{a+3} \\=\frac{(a+3)^2}{(a+3)(a-3)} *\frac{3(a-3)}{a+3} \\=\frac{3(a+3)^2}{(a+3)^2} \\=3

d.

\frac{3x^2-6x}{3x+1} *\frac{x+3x^2}{x^2-4x+4} \\=\frac{3x(x-2)}{3x+1} *\frac{x(1+3x)}{x^2-2x-2x+4} \\=\frac{3x(x-2)}{3x+1} *\frac{x(1+3x)}{x(x-2)-2(x-2)} \\=\frac{3x(x-2)}{3x+1} *\frac{x(1+3x)}{(x-2)(x-2) } \\=\frac{3x^2}{x-2)}

e.

\frac{2x^2-10x+12}{x^2-4} *\frac{2+x}{3-x} \\=\frac{2[x^2-5x+6]}{x^2-2^2} *\frac{2+x}{-(-3+x)} \\=\frac{2[x^2-2x-3x+6]}{(x+2)(x-2)} *\frac{x+2}{-(x-3)} \\=\frac{2[x(x-2)-3(x-2)]}{(x+2)(x-2)} *\frac{x+2}{-(x-3)} \\=\frac{2(x-2)(x-3)}{(x+2)(x-2)} *\frac{x+2}{-(x-3)} \\=\frac{2}{-1} \\=-2

k.

\frac{6x^2-11x-10}{6x^2-5x-6} *\frac{6-4x}{25-20x+4x^2} \\=\frac{6x^2-15x+4x-10}{6x^2-9x+4x-6} *\frac{-4x+6}{4x^2-10x-10x+25} \\=\frac{3x(2x-5)+2(2x-5)}{3x(2x-3)+2(2x-3) } *\frac{-2(2x-3)}{2x(2x-5)-5(2x-5)} \\=\frac{(2x-5)(3x+2)}{(2x-3)(3x+2)} *\frac{-2(2x-3)}{(2x-5)(2x-5)} \\=\frac{-2}{2x-5}

7 0
3 years ago
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