The discriminante :
b^2-4ac
1^2 - 4 * -2 * -28 = 1 - 224 = -223
When the discriminant (b^2-4ac) is less than 0, the equation had no real solutions.
-223<0, so, 2x^2+x-28 = 0 has no real solutions.
Hope that helps :)
Answer:
Step-by-step explanation:
In order to find the answer to this question you must add 7 on both sides.
Hope this helps.
Answer:
11 1/4 or 45/5
Step-by-step explanation:
just multiply 5 * 2 1/4
And thats ur answer
<h3>Solution:-</h3>
⟹( 4x + 3 )( 2x - 5 )
⟹( 4x × 2x ) - ( 4x × - 5) + ( 3 × 2x )-( 3×-5 )
⟹8x²- ( - 20x ) + 6x - ( - 15 )
⟹8x² + 20x + 6x + 15
<h3>⟹8x² + 26x + 15</h3>
Answer:
10. ⅔ − ∛e
11. 79 + 3√3
Step-by-step explanation:
10. ∫ (1 + 1/x) dx
∫ dx + ∫ (1/x) dx
These are both standard integrals.
x + ln|x| + C
Evaluate between x = ∛e and x = 1.
(1 + ln|1| + C) − (∛e + ln|∛e| + C)
1 + 0 + C − ∛e − ⅓ − C
⅔ − ∛e
11. ∫₁³ (4x³ + ³/₂√x) dx
∫₁³ 4x³ dx + ∫₁³ (³/₂ x^½) dx
(x⁴ + x^(³/₂) + C) |₁³
(x⁴ + x√x + C) |₁³
(3⁴ + 3√3 + C) − (1⁴ + 1√1 + C)
81 + 3√3 + C − 1 − 1 − C
79 + 3√3