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3 years ago

12

WILL MARK BRANLIEST!! HELP ASAP!!!!!!!!!!!

1 answer:

Reika [66]3 years ago

5 0

55/4 or 13 3/4
Hope thats right

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The perimeter of a rectangular deck is 4 times its width. If the deck's perimeter is 30 feet, what is the deck's area?

RSB [31]

Answer:

i think it is 120

Step-by-step explanation:

4 multiplied by 30 is 120

4 0

3 years ago

There are 50 students in a class. If 14% are absent on a particular day, find the number of students present in the class. What

Tcecarenko [31]

Answer:

i THINK 43% but im not for sure

Step-by-step explanation:

14% of 50 is 7

so 50-7=43

43(percent there)+7(percent gone)=50 (number of students)

SO 43% is still there.

SORRY IF IM WRONG have a good night :)

3 0

3 years ago

A rectangular prism is 4 metters long, 5 meters wide, and has a height of 7 meters, What is the surface area?

Natalija [7]

Hello! I believe the Surface Area to a rectangular prism= 2(4x5+5x7+4x7). Let me know if i'm wrong. Anyways hope this helps!

5 0

4 years ago

Amelie needs 2| 3/8 cups flour for one recipe and 1| 1/3 cups of flour for another recipe.

ryzh [129]

Answer:

3 and 17/24 cups of flour

Step-by-step explanation:

You need to make the denominator the same so find what number the 8 and 3 can both be turned into to make the same number. They can both be made into a 24. 8x3=24 so you multiply the 3 by 3 making 9. Do the same to the 1/3, multiplying both by 8 making 8/24.

2 9/24 and 1 8/24 which can be made into 3 17/24

5 0

3 years ago

Read 2 more answers

2x2 – 5x + 67 = 0<br> What would be your first step in completing the square for the equation above?

7nadin3 [17]

Answer:

The first step is to divide all the terms by the coefficient of $x^{2}$ which is 2.

The solutions to the quadratic equation $2x^2\:-\:5x\:+\:67\:=\:0$ are:

$x=\frac{5}{4}+i\frac{\sqrt{511}}{4},\:x=\frac{5}{4}-i\frac{\sqrt{511}}{4}$

Step-by-step explanation:

Considering the equation

$2x^2\:-\:5x\:+\:67\:=\:0$

The first step is to divide all the terms by the coefficient of $x^{2}$ which is 2.

so

$\frac{2x^2-5x}{2}=\frac{-67}{2}$

$x^2-\frac{5x}{2}=-\frac{67}{2}$

Lets now solve the equation by completeing the remaining steps

Write equation in the form: $x^2+2ax+a^2=\left(x+a\right)^2$

Solving for $a$ ,

$2ax=-\frac{5}{2}x$

$a=-\frac{5}{4}$

$\mathrm{Add\:}a^2=\left(-\frac{5}{4}\right)^2\mathrm{\:to\:both\:sides}$

$x^2-\frac{5x}{2}+\left(-\frac{5}{4}\right)^2=-\frac{67}{2}+\left(-\frac{5}{4}\right)^2$

$x^2-\frac{5x}{2}+\left(-\frac{5}{4}\right)^2=-\frac{511}{16}$

Completing the square

$\left(x-\frac{5}{4}\right)^2=-\frac{511}{16}$

Since, you had required to know the first step in completing the square for the equation above, I hope you have got the point, but let me quickly solve the remaining solution.

For $f^2\left(x\right)=a$ the solution are $f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

Solving

$x-\frac{5}{4}=\sqrt{-\frac{511}{16}}$

$x-\frac{5}{4}=\sqrt{-1}\sqrt{\frac{511}{16}}$

$x-\frac{5}{4}=i\sqrt{\frac{511}{16}}$ ∵ Applying imaginary number rule $\sqrt{-1}=i$

$x-\frac{5}{4}=i\frac{\sqrt{511}}{\sqrt{16}}$

$-\frac{5}{4}=i\frac{\sqrt{511}}{4}$

$x=\frac{5}{4}+i\frac{\sqrt{511}}{4}$

Similarly, solving

$x-\frac{5}{4}=-\sqrt{-\frac{511}{16}}$

$x-\frac{5}{4}=-i\frac{\sqrt{511}}{4}$ ∵ Applying imaginary number rule $\sqrt{-1}=i$

$x=\frac{5}{4}-i\frac{\sqrt{511}}{4}$

Therefore, the solutions to the quadratic equation are:

$x=\frac{5}{4}+i\frac{\sqrt{511}}{4},\:x=\frac{5}{4}-i\frac{\sqrt{511}}{4}$

4 0

3 years ago