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In-s [12.5K]
3 years ago
14

Write a polynomial f(x) that satisfies the given conditions.

Mathematics
1 answer:
patriot [66]3 years ago
6 0

Answer:

f(x) = (x-4)(x-\frac{1}{2})^2 = x^3-5x^2+4.25x -1

Step-by-step explanation:

Recall, if we have a polynomial of the form (x-a)^k \cdot (x-b)^m, then we say that a is a zero of multiplicity k and b is a zero of multiplicty m. For example, in the polynomial of the form (x+5)^10(x-2)^3 -5 is a zero of multiplicity 10 and 2 is a zero of multiplicity 3. If we want to know the degree of the polynomial,  just add the multiplicity of both zeros (13 in our example).

In this case, we know that the degree of our polynomial should be at least 3(multiplicity 2 and multiplicity 1). So, lets take the polynomial of the form

f(x)=(x-a)(x-b)^2).

In here, a is a zero with multiplicity 1 and b is a zero with multiplicity 2. We are also given that

f(0) = -1 = (0-a)(0-b)^2 = -a\codt b^2.

Which implies that 1 = a\cdot b^2. Since the square of any number is a positive number, it must happen that a>0. So, we have that

b= \pm \sqrt[]{\frac{1}{a}}.

We can choose any value of a and solve for b. Let us choose a=4. So we can have b=1/2 or b=-1/2. Let's use b=1/2. So our polynomial would be

f(x) = (x-4)(x-\frac{1}{2})^2 = x^3-5x^2+4.25x -1

which we can easily check that f(0)=-1.

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Find all zeros for (2x-1)(x-5)
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Read 2 more answers
Order the following numbers from greatest to least: 7.321, 7.3, 7.065, 7.65
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The order for the given decimal numbers, from the greatest to the least, is: D. 7.65, 7.321, 7.3, 7.065.

<h3>How to Order a Set of Decimal Numbers?</h3>

When considering the order of a set of decimal numbers, the value larger the digit that is close to the decimal point, the larger the decimal number, and vice versa.

Given the following set of decimal numbers, 7.321, 7.3, 7.065, 7.65.

Notice that all decimal numbers start with 7. So, the digit close to the decimal point is what we will consider to determine which decimal number is greater or the least.

The decimal number that has the greater digit that is close to the decimal point is, 7.65, followed by 7.321, then 7.3.

The decimal number with the least digit closer to the decimal point is 7.065.

Therefore, the order for the given decimal numbers, from the greatest to the least, is: D. 7.65, 7.321, 7.3, 7.065.

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2 years ago
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