12c - 4 = 14c - 10<br><br> c = ?<br><br> !!!

Giving out BRAINLIEST, THANKS, 5 STARS, and POINTS if answered correctly!<br> PLS HELP ASAP!

AnnyKZ [126]

Answer:

it is the first option

Step-by-step explanation:

the middle (median)is 31 and where the Q starts is 26

7 0

3 years ago

A regular heptagon has a radius of approximately 27.87 cm and the length of each side is 24.18 cm. what is the approximate area

aniked [119]

The area of the regular heptagon which has a radius of approximately 27.87 cm and the length of each side is 24.18 cm is 2125 cm².

<h3>What is the area of a heptagon?</h3>

Heptagon is the closed shape polygon which has 7 sides and 7 interior angles.

The area of the regular heptagon is found out using the following formula.

$A=\dfrac{7a}{4}\cot \left(\dfrac{180}{7}\right)$

Here, (<em>a</em>) is the length of the heptagon.

A regular heptagon has a radius of approximately 27.87 cm and the length of each side is 24.18 cm. Put the value of side in the above formula,

$A=\dfrac{7\times24.18}{4}\cot \left(\dfrac{180}{7}\right)\\A\approx 2125\rm\; cm^2$

Hence, the area of the regular heptagon which has a radius of approximately 27.87 cm and the length of each side is 24.18 cm is 2125 cm².

Learn more about the area of a heptagon here;

brainly.com/question/26271153

3 0

2 years ago

The area of the bottom of the two cylindrical vessels A and B is 400cm ^ 2 and 300cm ^ 2, respectively. A jar is about 6cm hig

Sonbull [250]

Answer:

Water in container B will be at 6.own

Step-by-step explanation:

calculate the volume in cont. A

VoA=400×6

=2400cm cube

VoB=420ml

=420cm cube [1ml=1cm cube]

now add both volumes

V=2400+420

=2820cm cube

Now,

2820 cm cube in jar B so

2820=420×h

h=6.71

4 0

3 years ago

1/6d + 2/3 = 1/4(d-2) how to solve

natita [175]

Greetings!

Solve for d.
$1/6d + 2/3 = 1/4(d-2)$
Distribute the Parenthesis.
$1/6d + 2/3 = 1/4*d+1/4*-2$
$1/6d + 2/3 = 1/4d+1/4*-2/1$
$1/6d + 2/3 = 1/4d-2/4$
Reduce.
$1/6d + 2/3 = 1/4d-1/2$
Add -2/3 to both sides.
$(1/6d + 2/3)+(-2/3)=(1/4d-1/2)+(-2/3)$
Simplify.
$1/6d=1/4d-3/6-4/6$
$1/6d=1/4d-7/6$
Add -1/4d to both sides.
$(1/6d)+(-1/4d)=(1/4d-7/6)+(-1/4d)$
Simplify.
$2/12d)-3/12d=-7/6$
$-1/12d=-7/6$
Divide both sides by -1/12.
$(-1/12d)/-1/12=(-7/6)/-1/12$
Simplify.
$d=(-7/6)*-12/1$
$d=84/6$
Reduce.
$d=14/1$
$d=14$

Hope this helps.
-Benjamin

7 0

4 years ago

1. One week Carlos bought 3 bags of Tabitha Tidbits and 4 bags of Figaro Flakes for $43.00. The next week he bought 3 bags of Ta

d1i1m1o1n [39]

Tabitha Tidbits costs $7 per bag, and Figaro Flakes is $5.50 per bag.
You need to set up a system of equations. Use "x" for Tabitha Tidbits and "y" for Figaro Flakes, and let the total cost of each trip equal c. Using the equation ax+by=c, substitute the cost of each trip in for c, and the number of bags for each food for a and b respectively. The two equations will be:
3x+4y=43
3x+6y=54
Isolate x in the first equation and you will get:
x=(43-4y)/3
Substitute the above equation for x into the other equation:
3*((43-4y)/3)+6y=54
Isolate y in this equation, and you will get 11/2, which is 5.5
So the cost of one bag of Figaro Flakes is $5.50
Now substitute this into the equation where you isolated x:
(43-4(5.5))/3
You will get x=7, so a bag of Tabitha Tidbits is $7

3 0

3 years ago

12c - 4 = 14c - 10 c = ? !!!